$\bold{Rays:}\ \overrightarrow{EA},\ \overrightarrow{EB},\ \overrightarrow{EC},\ \overrightarrow{ED},\ \overrightarrow{DE},\ \overrightarrow{BE}\\\\\bold{Lines:}\ \overleftrightarrow{ED},\ \overleftrightarrow{BE}$

Step-by-step explanation:

Look at the picture.

4 0

3 years ago

(Algebra || is Soo hard!) Please someone help me:)

frez [133]

Answer:

Step-by-step explanation:

B is the correct answer

2+i/5= i=5 +=-

have a nice day

4 0

4 years ago

Read 2 more answers

In the diagram abc=adb=90, ad=p and dc=q. Use similar triangles to show that x2=pz<br> plzz anyoneee

kramer

Answer:

By comparing the ratios of sides in similar triangles ΔABC and ΔADB,we can say that $x^{2} =pz$

Step-by-step explanation:

Given that ∠ABC=∠ADC, AD=p and DC=q.

Let us take compare Δ ABC and Δ ADB in the attached file , ∠A is common in both triangles

and given ∠ABC=∠ADB=90°

Hence using AA postulate, ΔABC ≈ ΔADB.

Now we will equate respective side ratios in both triangles.

$\frac{AB}{AC}= \frac{AD}{AB}=\frac{BD}{BC}$

Since we don't know BD , BC let us take first equality and plugin the variables given in respective sides.

$\frac{x}{z}= \frac{p}{x}$

Cross multiply

$x^{2}=pz$

Hence proved.

7 0

4 years ago