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Tamiku [17]
3 years ago
9

Melinda poured herself 20 ounces of orange juice for breakfast. By the end of her meal, she only has 4 ounces left. What scale f

actor represents the amount of orange juice she has left ?
Mathematics
1 answer:
Advocard [28]3 years ago
4 0

Answer:my profile pic is a throwing dart not a ding dong dirty

Step-by-step explanation:

You might be interested in
Write the equation in slope intercept form of the line that passes through the point (1,-3) and a slope of -2
Alborosie

Answer:y=-2x-1


Step-by-step explanation:

(1,-3) and a slope of -2

Use Formula

Y= mx +b to find b. By using the slope and point given .

M is slope

Y is -3

X Is 1



Y=mx+b


-3= -2(1)+b


-3= -2+b


-3+2=b


-1=b


Now create the equation by inputting the slope they gave you which is -2 and answer we solved for b which is -1 .


Y= -2x-1

4 0
3 years ago
how much must you deposit in an account that pays 8% annual interest compounded monthly to have a balance of $1,000 after one ye
strojnjashka [21]

Answer:

\$923.36  

Step-by-step explanation:

we know that

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=1\ year\\ A=\$1,000\\ r=0.08\\n=12  

substitute in the formula above  and solve for P

\$1,000=P(1+\frac{0.08}{12})^{12*1}  

P=\$1,000/(1+\frac{0.08}{12})^{12*1}=\$923.36  

5 0
3 years ago
HELP ASAP
maxonik [38]

Answer:

Shape B

Step-by-step explanation:

If you reflect Shape C over X it fits into Shape D. Then reflected over Z it fits into Shape B. Therefore, the final shape would be B.

6 0
3 years ago
12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5
Gnesinka [82]

\large\underline{\sf{Solution-}}

Given that,

In <u>triangle TPQ, </u>

  • RS || PQ,

  • RS = 3 cm,

  • PQ = 6 cm,

  • ar(∆ TRS) = 15 sq. cm

As it is given that, <u>RS || PQ</u>

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

\rm\implies \: \triangle TPQ \:  \sim \: \triangle TRS \:  \:  \:  \:  \:  \:  \{AA \}

<u>Now, We know </u>

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)}  = \dfrac{ {PQ}^{2} }{ {RS}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{ {6}^{2} }{ {3}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{36 }{9}

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = 4

\rm\implies \:ar( \triangle \: TPQ)  = 60 \:  {cm}^{2}

3 0
2 years ago
Suppose that $9500 is placed in an account that pays 8% interest compounded each year.
Blababa [14]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$9500\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{each year, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}


\bf A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 1}\implies A=9500(1.08)\implies \boxed{A=10260} \\\\\\ \stackrel{\textit{after 2 years, t = 2}}{A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 2}}\implies A=9500(1.08)^2\implies \boxed{A=11080.8}

6 0
3 years ago
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