Answer: (3b + 5)(3b - 5)
Because both terms, 9b² and 25, are perfect squares, you can factor by taking the square roots of both terms.
The square root of 9b² is 3b (3b × 3b = 9b²).
The square root of 25 is 5 (5 × 5 = 25).
9b² - 25 has a negative, so the factored expression would be
(3b + 5)(3b - 5). The signs (+ and -) alternate in this case because the expression, 9b² - 25, has no middle term.
You can check your work by using FOIL. See the attachment below.
F irst
O utside
I nside
L ast
R=i/pt
R=16/200*2=0.04*100=4%
Answer:
Period ⇒ 40
Amplitude ⇒ 12
Mid-line ⇒ 32
Step-by-step explanation:
The table is counting by 4's and the period is the amount of space between 2 peaks. In this scenario, we can find the peaks by looking for two of the same highest value (44). We can see that x=40 has a value of 44 while the other is actually not shown because it would be located at x=0. Therefore the period is 40
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The amplitude can be found by using the following:

Our maximum is 44 and our minimum is 20.



The amplitude is 12
The amplitude is the distance from the peak to the mid-line. To find the mid-line, we can either subtract our amplitude from our maximum value (44) or add our amplitude to our minimum value (20)
44 - 12 = 32
20 + 12 = 32
Therefore our mid-line is y = 32
~Hope this helps!~
For part A: you will get 3 linear factors (as the degree of the polynomial is 3). perform the division using (x-1) as your known factor and you will get (x-1)(2x²+11x+15). you can then factor the (2x²+11x+15) to get 2x^3 + 9x^2 + 4x - 15 = (x-1)(2x+5)(x+3)
for part B: since 2x+5 will provide the greatest value (assuming x>0) of the 3 factors, then 2x+5=13. solve to get x=4. if x is 4, then the dimensions are 3'x13'x7' [just sub 4 into the x's for each factor]
for part C: as to the graphing calculator, I don't have one. However, if you solve each linear factor for when it is 0, those values will be the x-intercepts. So your graph should cross the x-asix at 1, -5/2, and -3