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tangare [24]
3 years ago
8

PLEASE HELP ME BEFORE I SOIL MY TUNIC OUT OF FRUSTRATION!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
7 0
The answer is at the end of turn 3.
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PLS HELP PLS :DDD (NOOO LINKS)
Sati [7]

Step-by-step explanation:

V=πr2h

3

r Radius

h Height

6 0
3 years ago
Simplify (19x2 + 16x + 45) - (9x2 + 13x + 23).
Yuri [45]
19x2-9x2= 10x2
16x-13x= 3x
45-23= 22

(10x2+3x+22)

8 0
3 years ago
Nick's dad wanted to measure the length of his backyard and asked Nick to do this with his footsteps. Since it was winter, they
Lerok [7]

Answer:

2244 cm

Step-by-step explanation:

The first first thing we must do is find the LCM of the following numbers

(51; 68) = 204.

This means that the first time they coincide is at 204.

Now, since his steps always coincide after 204

In Nick's case

Nick's 204 ÷ 51 = 4th step

and in the case of the father

204 ÷ 68 of his father = 3rd step.

Which means that in the 204 cm distance, there will be a total of 6 foot steps, except in the first 204 cm when your "initial" step is counted.

Replacing these values we have that the total distance will be:

67-1 (initial step) / (6 * 204) = 2244 cm

7 0
3 years ago
Find the value of x. Round to the nearest tenth.
Aliun [14]

Answer:

Step-by-step explanation:

Triangle XYZ is a right angle triangle.

From the given right angle triangle

XZ represents the hypotenuse of the right angle triangle.

With ∠34 as the reference angle,

YZ represents the adjacent side of the right angle triangle.

XY represents the opposite side of the right angle triangle.

To determine x, we would apply the Cosine trigonometric ratio

Cos θ = opposite side/hypotenuse. Therefore,

Cos 34 = x/28

x = 28Cos34 = 28 × 0.8290

x = 23.212

To the nearest tenth, it becomes

23.2

7 0
4 years ago
The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure
Novosadov [1.4K]

Hello!

The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure?  

Use 3.14 to approximate π .  


Enter your answer in the box.  in.³

Data: (Cylinder)

h (height) = 7 in

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: \pi \approx 3.14

V (volume) = ?

Solving: (Cylinder volume)

V = \pi *r^2*h

V = 3.14 *2.5^2*7

V = 3.14*6.25*7

V = 137.375 \to \boxed{V_{cylinder} \approx 137.38\:in^3}

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4* \pi * \dfrac{r^3}{3} , but we have a hemisphere, so the formula will be half the volume of the hemisphere V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}

Formula: (Volume of the hemisphere)

V = 2* \pi * \dfrac{r^3}{3}

Solving:

V = 2* \pi * \dfrac{r^3}{3}

V = 2*3.14 * \dfrac{2.5^3}{3}

V = 2*3.14 * \dfrac{15.625}{3}

V = \dfrac{98.125}{3}

\boxed{ V_{hemisphere} \approx 32.70\:in^3}

Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)

Volume of the figure = cylinder volume + hemisphere volume

Volume of the figure = 137.38 in³ + 32.70 in³

Volume\:of\:the\:figure =170.08 \to \boxed{\boxed{\boxed{Volume\:of\:the\:figure = 170\:in^3}}}\end{array}}\qquad\quad\checkmark

_______________________

I Hope this helps, greetings ... Dexteright02! =)

5 0
3 years ago
Read 2 more answers
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