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SCORPION-xisa [38]

3 years ago

6

(4a + 2) (6a ^2 - a + 2 )

2 answers:

IRINA_888 [86]3 years ago

8 0

Answer:

16a^2+2

Step-by-step explanation:

Masteriza [31]3 years ago

7 0

<h3> $(4a + 2)(6a {}^{2} - a + 2) \\ = 4a(6a {}^{2} - a + 2) + 2(6a {}^{2} - a + 2) \\ = 24a {}^{3} - 4a {}^{2} + 8a + 12a {}^{2} - 2a + 4 \\ = 24a {}^{3} + 8a {}^{2} + 6a + 4$ </h3><h2>♧Solved</h2>

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Simplify the expression using long division.

zheka24 [161]

Answer: B, quotient 4x - 5 and remainder -6

Step-by-step explanation:

(4x^2 - 13x - 4) + (x - 2)

Remove the parentheses

4x^2 - 13x - 4 + x - 2

Add -13x and x

4x^2 - 12x - 4 - 2

Subtract 2 from -4

4x^2 - 12x - 6

I know this isn’t fully the correct answer but try option B

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kherson [118]

Answer:

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write a division problem that will have 2-digit quotient and another division problem that will have a 3-digit quotient. explain

shusha [124]

Answer:

brainly.com/question/2565047

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3 years ago

Kay [80]

Answer:

$\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}$

$4.535 \leq \sigma^2 \leq 7.602$

Now we just take square root on both sides of the interval and we got:

$2.2 \leq \sigma \leq 2.8$

And the best option would be:

A. 2.2 < σ < 2.8

Step-by-step explanation:

Information provided

$\bar X=32.1$ represent the sample mean

$\mu$ population mean

s=2.4 represent the sample standard deviation

n=83 represent the sample size

Confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom are given by:

$df=n-1=83-1=82$

The Confidence is given by 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , the critical values for this case are:

$\chi^2_{\alpha/2}=62.132$

$\chi^2_{1- \alpha/2}=104.139$

And replacing into the formula for the interval we got:

$\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}$

$4.535 \leq \sigma^2 \leq 7.602$

Now we just take square root on both sides of the interval and we got:

$2.2 \leq \sigma \leq 2.8$

And the best option would be:

A. 2.2 < σ < 2.8

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3 years ago

1,760 yards = <br> miles

devlian [24]

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