9+8 is the commutative property
Oof, this is surely a tough one. But, if I'm looking at this correctly, than I think you were in the right mindset when trying to figure both of them out. Like, for #18, think about the formula; P(B|A) = P(A and B)/P(A). So, based on the question, you can let not rolling a 1 on the blue cube be A, and rolling a 1 on the red cube be B. Now, personally, I prefer using the decimals when heading into the equations, but I'll convert the product into a fraction for the instruction's sake. 0.02777777778 + 0.13888888889 = 1/6. 1/6 ≈ 17.7%. You can do the same for #19, the overall outcome would be 5/6, which would be about 83%. Now, that's just me really attempting my hand at it, I will say, Math is far from my strong suite. But, in all honesty, I really am doing my best to help (and no, it's not because of what you offered, lol, more rather I want to help people who struggle with the same problems I do). Anyways, I hope this helps, and if you need more information, or anything, just let me know! Wish ya the best of luck!! ^u^
Answer:
Step-by-step explanation:
1). Geometric mean of a and b = 
Therefore, geometric mean of 2 and 50 = 
= 10
2). By geometric mean theorem,


e² = 6 × 24
e = √144
e = 12
Similarly, 

d² = 6 × 30
d = √180
d = 6√5
And 

c² = 30 × 24
c = √720
c = 12√5
To solve this, you need to isolate/get the variable "u" by itself in the inequality: u = unknown number
2u - 3 < 1 Add 3 on both sides
2u - 3 + 3 < 1 + 3
2u < 4 Divide 2 on both sides to get "u" by itself
u < 2 (u is any number less than 2)
When the inequality sign is >/< (greater than/less than), the dot/endpoint is an open/unfilled circle.
When the inequality sign is ≥/≤ (greater than or equal to/less than or equal to), the dot is a closed/filled circle.
u < 2
Start making a ray by placing an open circle on 2(click on the dot/endpoint to change it to be open if it isn't already), then have the ray point left where the numbers would be decreasing because "u" is any number less than 2. If you can place the end of the ray at the end of the number line.