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3 years ago

Solve the following system of equations. 1.) x - 2y = 6 2.) 2x - 4y = 10

Mathematics

2 answers:

sesenic [268]3 years ago

7 0

Answer:

it's D 6,10

Step-by-step explanation:

k0ka [10]3 years ago

4 0

One way to solve this system of equations would be by substitution. It would helpful to write these equation in the form y=mx + b in order to substitute one equation to the other. We do as follows:

1.) x - 2y = 6
y = x/2 -3

2.) 2x - 4y = 10
y = x/2 - 5/2

As we look at the rearranged equations, we see that their slopes are equal which means they are parallel lines so they do not intersect at one point. There is no solution for this system of equations.

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Determine the currents in the picture

Elenna [48]

Answer:

The value of currents are $I_1=0A$ , $I_2=1A$ and $I_3=1A$ .

Step-by-step explanation:

The Ohm's law states that

$V=IR$

it is given that the V₁=3V and V₂=4V.

In a parallel circuit:

Voltage is same in each component

Sum of the currents equals to the total current that flows.

$I_2=I_1+I_3$ .... (1)

Equation for first loop is,

$V_1=4I_1+3I_2$

$3=4I_1+3I_2$ ..... (2)

Equation for second loop is,

$V_2=1I_3+3I_2$

$4=1I_3+3I_2$ ..... (3)

On solving (1), (2) and (3) we get

$I_1=0$

$I_2=1$

$I_3=1$

Therefore the value of currents are $I_1=0A$ , $I_2=1A$ and $I_3=1A$ .

6 0

3 years ago

Sweet t has 2 orange picks for every green pick. if six of the picks are green how many are orange.

klemol [59]

There 12 orange picks because 2 x 6 = 12

3 0

3 years ago

Read 2 more answers

A. x=51, y=63 b. x=77, y=63 c x=63, y=77 d x=77, y=65

vekshin1

The answer is b. x=77, y=63

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3 years ago

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Question 4 please. I will mark brainliest!! i would at least like the equation of the graph thank you

Anestetic [448]

Answer:

a. -3 < x ≤ 5

b. -3 ≤ y < 3

c. (0, 0)

d. x = -3, x = 1, x = 5

e. -3 < x ≤ - 1, and 1 ≤ x ≤ 3,

f. (-1, -1), and (3, -3)

Step-by-step explanation:

a. The domain of a function is the set of the possible independent variable values which is -3 < x ≤ 5

b. The range of a function is the set of the possible values of the dependent variable which is -3 ≤ y < 3

c. The y-intercept is the point the graph crosses the y-axis

The y-intercept in the graph is the point (0, 0)

d. f(x) ≥ 0 when x = -3, x = 1, x = 5

f(x) ≥ 0 over the following range; -3 < x ≤ - 1.5, 0 ≤ x ≤ 1.5, 4.5 ≤ x ≤ 5

e. The intervals over which f(x) is decreasing are;

-3 < x ≤ - 1, and 1 ≤ x ≤ 3,

f. The local minimums where f(x) has the minimum values are;

(-1, -1), and (3, -3)

3 0

3 years ago

HELP ME!! im so stumped. will give brainliest!

Olegator [25]

Answer:

$x=1+\sqrt{3}$ and $x=1-\sqrt{3}$

Step-by-step explanation:

We have been given the parabola with vertex (1, -9) and y intercept at (0, -6).

Now we need to find the x-intercepts of that parabola. So first we begin by finding the equation of parabola using vertex formula:

$y=a\left(x-h\right)^2+k$

Vertex for this formula is given by (h,k)

Compare that with given vertex (1,-9), we get: h=1, k=-9

So plug these into vertex formula:

$y=a\left(x-1\right)^2-9$ ...(i)

Plug given point (0, -6). into (i)

$-6=a\left(0-1\right)^2-9$

$-6=a\left(-1\right)^2-9$

$-6=a\left(1\right)-9$

$-6+9=a$

$3=a$

Plug a=3 into (i)

$y=3\left(x-1\right)^2-9$

Now to find x-intercept, we just plug y=0 and solve for x

$y=3\left(x-1\right)^2-9$

$0=3\left(x-1\right)^2-9$

$9=3\left(x-1\right)^2$

$3=\left(x-1\right)^2$

$\pm \sqrt{3}=x-1$

$1+\pm \sqrt{3}=x$

Hence final answer are

$x=1+\sqrt{3}$ and $x=1-\sqrt{3}$

4 0

3 years ago