Angle ABC is a right angle. I mean they are both right angles actually.
1) Consider the departure point is A (0,0).
After one hour flight with an angle of elevation of 10°, it travelled a distance of 550 mi. (speed 550 mi/h) and reached an altitude of H.
(Imagine a right triangle: Departure point A (0,0), with angle of elevation A= 10° and after one hour reaching a point B, at an altitude H, note that AB = hypotenuse-)
Let's calculate H (after 1 hour/flight)
sin10° = H/AB = H/550 and H= 95.5065 mi, Speed of H = 95.506 mi/h
2) The shadow is represented by the horizontal side, adjacent to 10°.
So when the plane is advancing at 550 mi/h, the shadow is stretched at a speed S.
Now let's calculate the length of the shadow (always after one hour flight)
Pythagoras: 550² =95.5065² +(length of shadow)²
And Length of shadow = 541.65 mi
S= 541.65/1 hour = 541.65 mi/h
Answer:
Step-by-step explanation:I just freaking love girls like their is this girl at school that will bend over and I
Answer:
Equation E, Equation B, Equation C are equivalent
Step-by-step explanation:
Given Equation:
0.6 + 15b + 4 = 25.6
Check all that applies
Equation A: 15b + 4 = 25.6
0.6 + 15b + 4 = 25.6
15b + 4 = 25.6 - 0.6
15b + 4 = 25
NOT CORRECT
Equation B: 15b + 4 = 25
0.6 + 15b + 4 = 25.6
15b + 4 = 25.6 - 0.6
15b + 4 = 25
CORRECT
Equation C: 3(0.6 + 15b + 4) = 76.8
0.6 + 15b + 4 = 25.6
Multiplying both sides by 3
(0.6 + 15b + 4) ×3 = 25.6 × 3
(0.6 + 15b + 4) ×3 = 76.8
CORRECT
Equation D: 15b = 25.6
0.6 + 15b + 4 = 25.6
NOT CORRECT
Equation E: 15b = 21
0.6 + 15b + 4 = 25.6
15b = 25.6 - 0.6 - 4
15b = 21
CORRECT
Equation E, Equation B, Equation C are equivalent