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ohaa [14]
2 years ago
13

ray is purchasing a laptop that is on sale for 25% off. he knows the function that represents the sale price of his laptop is c(

p) = 0.75p, where p is the original price of the laptop. he also knows he has to pay 8% sale's tax on the laptop. the price of the laptop with tax is f(c) = 1.08c, where c is the sale price of the laptop. determine the composite function that can be used to calculate the final price of ray's laptop by solving for f[c(p)]. f[c(p)] = 1.83p f[c(p)] = 1.83cp f[c(p)] = 0.81p f[c(p)] = 0.81cp
Mathematics
2 answers:
Agata [3.3K]2 years ago
6 0
F[c(p)] = 0.81p. I hope this helps :) Please give me a rate and thanks :P
Arlecino [84]2 years ago
5 0

Answer:

f[c(p)]= 0.81p

Step-by-step explanation:

Given function that shows the the sale price of his laptop,

c(p) = 0.75p ----(1),

While, the function that shows the final price of laptop after sales tax,

f(c) = 1.08c

⇒ f[c(p)] = 1.08c(p)  ( c is the function of p so c can be replace by c(p) )

⇒ f[c(p)] = 1.08(0.75p)  ( From equation (1) )

⇒ f[c(p)]= 0.81p

Which is the required composite function.

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MATH HELP!!! 100PTS!!!
Lostsunrise [7]

Answer:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Step-by-step explanation:

<u>Given functions</u>:

  p(x)=2x-4

  r(x)=\dfrac{6x-1}{9x+1}

Solve for p(x) = r(x):

\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

Therefore:

a=18, \quad b=-40, \quad c=-3

Substitute the values of a, b and c into the <u>quadratic formula</u> and solve for x:

\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}

Therefore, the solutions are:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Learn more about quadratic equations here:

brainly.com/question/27750885

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