Answer:
The probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.
Step-by-step explanation:
Let <em>X</em> = the number of miles Ford trucks can go on one tank of gas.
The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 350 miles and standard deviation, <em>σ</em> = 10 miles.
If the Ford truck runs out of gas before it has gone 325 miles it implies that the truck has traveled less than 325 miles.
Compute the value of P (X < 325) as follows:
Thus, the probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.
<span> £536,521.
</span>6,521.
6,000
the thousands place
Answer:
The answer is 19.75
Step-by-step explanation:
You multiply the one in the brackets first
Answer:
(-4-5)0=1 because parentheses is raised to the zero power
or this becomes (-4[-5*0])=(-40)=1
or,...
(1/-45)0=(1/-1024)0=(-1/1024)0=1Step-by-step explanation:
Answer:
z = 1.960
Step-by-step explanation:
The sample proportion is:
p = 715 / 2684 = 0.2664
The standard error is:
σ = √(pq/n)
σ = √(0.266 × 0.734 / 2684)
σ = 0.0085
For α = 0.05, the confidence level is 95%. The z-statistic at 95% confidence is 1.960.
The margin of error is 1.960 × 0.0085 = 0.0167.
The confidence interval is 0.2664 ± 0.0167 = (0.2497, 0.2831).
The upper limit is 28.3%, so the journal can conclude with 95% confidence that the true percentage is less than 29%.
