Question

Plot the following points and find the area of the figure. (3,2); (-3,2); (-3,-3); (3,-3)

Answer 1

We have been given 4 points $(3,2), (-3,2), (-3,-3), (3,-3)$. We are asked yo plot these points on coordinate plane and find the area of the figure.

Upon plotting our given points, we will get a rectangle as shown in the attached file.  

We can see that the width is 5 units that is difference between y-coordinates of point $(3,2)\text{ and }(3,-3)$.

$\text{Width}=2-(-3)=2+3=5$

We can see that the length of rectangle is 6 units that is difference between x-coordinates of point $(-3,2)\text{ and }(3,2)$.

$\text{Length}=3-(-3)=3+3=6$

We know that area of rectangle is length times width.

$A=\text{Length}\times \text{Width}$

$A=6\times 5$

$A=30$

Therefore, the area of the figure would be 30 square units.