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2 years ago

Four bags of sunflower seeds were shared equally among 9 basketball players. What fraction of a bag did each player get?

Mathematics

2 answers:

olasank [31]2 years ago

8 0

The answer is 36, all you had to do is multiply 9x4

Lunna [17]2 years ago

3 0

4/9 ... I think that's it
.44 (repeating) as a decimal
You're dividing four by nine but it can't really be simplified...

You might be interested in

350/100 as a decimal and a percentage

Step2247 [10]

Decimal: 3.5 350 divided by 100 = 3.5 Percentage: 350% Move the decimal 2 times to the right 3.5 -> 350 Add a percent sign

3 0

3 years ago

Verify: sec^2x+tan^2x=2sec^2x-1

Jlenok [28]

Answer:

see explanation

Step-by-step explanation:

Using the identity

tan²x = sec²x - 1

Consider left side

sec²x + tan²x

= sec²x + sec²x - 1

= 2sec²x - 1

= right side , thus verified

8 0

2 years ago

A rose garden Is formed by jolning a rectangle and a semicircle, as shown below. The rectangle Is 23 ft long and 14 ft wide.Find

Ratling [72]

Answer:

Area of the garden:

$\begin{equation*} 398.93\text{ ft}^2 \end{equation*}$

Explanation:

Given the below parameters;

Length of the rectangle(l) = 23 ft

Width of the rectangle(w) = 14 ft

Value of pi = 3.14

Since the width of the rectangle is 14 ft, so the diameter(d) of the semicircle is also 14 ft.

The radius(r) of the semicircle will now be;

$r=\frac{d}{2}=\frac{14}{2}=7\text{ ft}$

Let's now go ahead and determine the area of the semicircle using the below formula;

$A_{sc}=\frac{\pi r^2}{2}=\frac{3.14*\left(7\right)^2}{2}=\frac{3.14*49}{2}=\frac{153.86}{2}=76.93\text{ ft}^2$

Let's also determine the area of the rectangle;

$A_r=l*w=23*14=322\text{ ft}^2$

We can now determine the area of the garden by adding the area of the semicircle and that of the rectangle together;

$\begin{gathered} Area\text{ of the garden = Area of semi circle + Area of rectangle } \\ =76.93+322 \\ =398.93\text{ ft}^2 \end{gathered}$

Therefore, the area of the garden is 398.93 ft^2

8 0

1 year ago

A manufacturer of college textbooks is interested in estimating the strength of the bindings produced by a particular binding ma

IrinaVladis [17]

Answer:

538 books should be tested.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How many books should be tested to estimate the average force required to break the binding to within 0.08 lb with 99% confidence?

n books should be tested.

n is found when $M = 0.08$

We have that $\sigma = 0.72$

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.08 = 2.575*\frac{0.72}{\sqrt{n}}$

$0.08\sqrt{n} = 2.575*0.72$

$\sqrt{n} = \frac{2.575*0.72}{0.08}$

$(\sqrt{n})^{2} = (\frac{2.575*0.72}{0.08})^{2}$

$n = 537.1$

Rounding up

538 books should be tested.

6 0

2 years ago

Solve for x. 3x/6 + 2 = 8 x = 3 x = 12 x = 24

Advocard [28]

$\frac{3x}{6} + 2 = 8 \\ \frac{3x}{6} = 8 - 2 \\ \frac{3x}{6} = 6 \\ 3x = 36 \\ x = 36 \div 3 \\ x = 12$
So; the answer is: 12

8 0

2 years ago