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Karolina [17]
2 years ago
9

Write a rational expression in which x simplifies to x+3/x-10

Mathematics
1 answer:
tino4ka555 [31]2 years ago
4 0

Answer:

Below.

Step-by-step explanation:

[(x - 3)(x +3)] / [(x - 3)(x - 10)]

The x-3 cancels out.

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Margaret [11]

Lets use a rectangle as the example because I dont know what kind of shape you're looking for.

Area of a rectangle = length * width

Length (l) = 62

Width (w) = x

Area = 744

744 = 62 * x

Divide both sides by 62

744/62 = 12

12 = x

That means the width would equal 12

12 * 62 = 744

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Step-by-step explanation:

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Write an algebraic expression to represent the new x-coordinate after a reflection across the x-axis given any initial x-coordin
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Step-by-step explanation:

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2 years ago
What is the sq. root of 0.09?
Jobisdone [24]
This is pretty much asking "what squared it 0.09". The answer is 0.3, as 0.3 to the power of 2 is 0.09
7 0
3 years ago
Read 2 more answers
What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
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