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2 years ago

N the problem 4 × 12 = 48, which numbers are the factors?

Mathematics

1 answer:

Gre4nikov [31]2 years ago

5 0

The factor is, 4 and 12

A factor is a<span> number that divides another number evenly with no remainder. </span>

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Explain how to multiply the following whole numbers 21 x 14

Lesechka [4]

Answer:

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

________

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

Step-by-step explanation:

Given

$21\:\times \:14$

Line up the numbers

$\begin{matrix}\space\space&2&1\\ \times \:&1&4\end{matrix}$

Multiply the top number by the bottom number one digit at a time starting with the ones digit left(from right to left right)

Multiply the top number by the bolded digit of the bottom number

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

Multiply the bold numbers: 1×4=4

$\frac{\begin{matrix}\space\space&2&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&4\end{matrix}}$

Multiply the bold numbers: 2×4=8

$\frac{\begin{matrix}\space\space&\textbf{2}&1\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}$

Multiply the top number by the bolded digit of the bottom number

$\frac{\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}$

Multiply the bold numbers: 1×1=1

$\frac{\begin{matrix}\space\space&\space\space&2&\textbf{1}\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&\space\space&1&\space\space\end{matrix}}$

Multiply the bold numbers: 2×1=2

$\frac{\begin{matrix}\space\space&\space\space&\textbf{2}&1\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&2&1&\space\space\end{matrix}}$

Add the rows to get the answer. For simplicity, fill in trailing zeros.

$\frac{\begin{matrix}\space\space&\space\space&2&1\\ \space\space&\times \:&1&4\end{matrix}}{\begin{matrix}\space\space&0&8&4\\ \space\space&2&1&0\end{matrix}}$

adding portion

$\begin{matrix}\space\space&0&8&4\\ +&2&1&0\end{matrix}$

Add the digits of the right-most column: 4+0=4

$\frac{\begin{matrix}\space\space&0&8&\textbf{4}\\ +&2&1&\textbf{0}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{4}\end{matrix}}$

Add the digits of the right-most column: 8+1=9

$\frac{\begin{matrix}\space\space&0&\textbf{8}&4\\ +&2&\textbf{1}&0\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{9}&4\end{matrix}}$

Add the digits of the right-most column: 0+2=2

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

Therefore,

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

________

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

6 0

2 years ago

Solve 3y - 15 = y+1 with steps shown

bija089 [108]

Answer:

y = 8

Step-by-step explanation:

Hello!

We can solve for y by isolating it.

<h3>Solve for y</h3>

3y - 15 = y + 1
3y - 15 - y = y +1 - y
2y - 15 = 1
2y - 15 + 15 = 1 + 15
2y = 16
y = 16/2
y = 8

The value of y is 8.

4 0

1 year ago

Read 2 more answers

A function has the function rule y = -7 x - 2. If the input is -4, what is the output? 26 -30 -26 14

GaryK [48]

Answer:

Step-by-step explanation:

Since the input is -4, x = -4. The equation then is y = -7(-4) -2

A negative times a negative is a positive, so -7 times -4 is 28.

Now the equation reads y = 28 - 2

Then obviously you just subtract the two and then you get 26.

5 0

3 years ago

Read 2 more answers

Find lim x->2 for f(x)=

TiliK225 [7]

LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)

<h3>What is the limit of a function ?</h3>

The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.

It is given that

lim x->2 for f(x)

$\lim_{x \rightarrow 2^-}f(x) = \lim_{x\rightarrow 2^+}f(x)$

f(x) = 2x+1 x ≤2

f(x)= x² , x >2

When both the function tends to 2

Left Hand Limit

f(x) = 2 *2 +1

f(x) = 5

Right Hand Limit

f(x) = x² ,

f(x) = 4

LHL in not equal to RHL , Therefore the limit does not exists.

To know more about Limit of a Function

brainly.com/question/7446469

#SPJ1

8 0

1 year ago

PLZZZZZ Help I will Give Brainliest

yarga [219]

Answer:

See below

Step-by-step explanation:

A) In part 1, the bus is increasing in speed. In part 2, the bus keeps a steady pace. In part 3, the bus is slowing down. In part 4, the bus is once again keeping a steady pace. In part 5, the bus is increasing in speed once again.

B) Parts 1 and 5 are increasing, part 3 is decreasing, and parts 2 and 4 are constant.

C) This graph is non-linear. Linear means straight, and this graph is constantly increasing and decreasing. Thus, it is non-linear.

7 0

3 years ago