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3 years ago

N the problem 4 × 12 = 48, which numbers are the factors?

Mathematics

1 answer:

Gre4nikov [31]3 years ago

5 0

The factor is, 4 and 12

A factor is a<span> number that divides another number evenly with no remainder. </span>

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Marina CMI [18]

both (0,350) and (250,700) fall in the shaded are

and check:

350 *3 = 1050, which is more than 1000 and more than double the amount of hotdogs ( 0)

700 *3 = 2100, so over 1000 and more than double the amount of hotdogs(250*2=500)

so those 2 are correct

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3 years ago

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timurjin [86]

Answer:

Step-by-step explanation:

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3 years ago

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HELP ME WITH THE EQUATION!!! IF ITS CORRECT ILL GIVE BRAINIST

Andrei [34K]

Answer:

The equation would be F = C - 3m

Step-by-step explanation:

Based on the chart, the fee for each movie you rent costs 3 dollars. The F is the monthly membership fee, the m is the number of movies rented, the 3 is the fee for each movie rented, & the C is the cost.

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3 years ago

-0.38 written as a fraction the 8 is a repeating decimal

Simora [160]

Answer:

$\frac{-7}{18}$

Step-by-step explanation:

The line in between the numerator and denominator serves as a division sign so, -7 divided by 18 equals -0.38 with the 8 repeating

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3 years ago

The population of a city in 2000 was 500,000 while the population of the suburbs of that city in 2000 was 700,000. Suppose that

Mnenie [13.5K]

Answer:

The population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

Step-by-step explanation:

6% of the city's population moves to the suburbs (and 94% stays in the city).
2% of the suburban population moves to the city (and 98% remains in the suburbs).

The migration matrix is given as:

$A= \left \begin{array}{cc} \\ C \\S \end{array} \right\left[ \begin{array}{cc} C&S\\ 0.94&0.06 \\0.02&0.98 \end{array} \right]$

The population in the year 2000 (initial state) is given as:

$\left[ \begin{array}{cc} C&S\\ 500,000&700,000 \end{array} \right]$

Therefore, the population of the city and the suburb in 2002 (two years after) is:

$S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\& \end{array} \right\left \begin{array}{cc} \end{array} \right\left[ \begin{array}{cc} 0.94&0.06 \\0.02&0.98 \end{array} \right]^2$

$A^{2} = \left[ \begin{array}{cc} 0.8848 & 0.1152 \\\\ 0.0384 & 0.9616 \end{array} \right]$

Therefore:

$S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\& \end{array} \right\left \begin{array}{cc} \end{array} \right \left[ \begin{array}{cc} 0.8848 & 0.1152 \\ 0.0384 & 0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 500,000*0.8848+700,000*0.0384& 500,000*0.1152 +700,000*0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 469280& 730720 \end{array} \right]$

Therefore, the population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

6 0

3 years ago