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Solnce55 [7]
3 years ago
7

Solve the equation: −4(m+6)=−8

Mathematics
1 answer:
WITCHER [35]3 years ago
6 0
M=-4
Hope this helps :)

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Sold the equation. Round to the nearest hundredth. <br><br>17 · <img src="https://tex.z-dn.net/?f=1.8%5E%7B-x%2B7%7D%20%3D%205"
svetlana [45]

Answer:

Final answer is approx x=4.26.

Step-by-step explanation:

Given equation is 1.8^{-x+7} = 5

Now we need to solve equation 1.8^{-x+7} = 5 and round to the nearest hundredth.

1.8^{-x+7} = 5

\log(1.8^{-x+7}) = \log(5)

(-x+7)\log(1.8) = \log(5)

(-x+7) = \frac{\log(5)}{\log(1.8)}

(-x+7) = \frac{0.698970004336}{0.255272505103}

-x+7 = 2.73813274192

-x = 2.73813274192-7

-x =−4.26186725808

x =4.26186725808

Round to the nearest hundredth.

Hence final answer is approx x=4.26.

4 0
3 years ago
Describe a pattern you notice when adding the sums of fractions with even denominators as opposed to those with odd denominators
GuDViN [60]
When adding fractions with even denominators, you will not get a whole number, there will be a 1/2. When adding fractions with odd denominators there will be a whole number.
8 0
3 years ago
Read 2 more answers
An object is heated to 100°. It is left to cool in a room that
stepladder [879]

Answer:

Step-by-step explanation:

Use Newton's Law of Cooling for this one.  It involves natural logs and being able to solve equations that require natural logs.  The formula is as follows:

T(t)=T_{1}+(T_{0}-T_{1})e^{kt} where

T(t) is the temp at time t

T₁ is the enviornmental temp

T₀ is the initial temp

k is the cooling constant which is different for everything, and

t is the time (here, it's in minutes)

If we are looking first for the temp after 20 minutes, we have to solve for the k value.  That's what we will do first, given the info that we have:

T(t) = 80

T₁ = 30

T₀ = 100

t = 5

k = ?

Filling in to solve for k:

80=30+(100-30)e^{5k} which simplifies to

50=70e^{5k} Divide both sides by 70 to get

\frac{50}{70}=e^{5k} and take the natural log of both sides:

ln(\frac{5}{7})=ln(e^{5k})

Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared).  That gives us:

-.3364722366=5k

Divide both sides by 5 to get that

k = -.0672944473

Now that we have a value for k, we can sub that in to solve for T(20):

T(20)=30+(100-30)e^{-.0672944473(20)} which simplifies to

T(20)=30+70e^{-1.345888946}

On your calculator, raise e to that power and multiply that number by 70:

T(20)= 30 + 70(.260308205) and

T(20) = 30 + 18.22157435 so

T(20) = 48.2°

Now we can use that k value to find out when (time) the temp of the object cools to 35°:

T(t) = 35

T₁ = 30

T₀ = 100

k = -.0672944473

t = ?

35=30+100-30)e^{-.0672944473t} which simplifies to

5=70e^{-.0672944473t}

Now divide both sides by 70 and take the natural log of both sides:

ln(\frac{5}{70})=ln(e^{-.0672944473t}) which simplifies to

-2.63905733 = -.0672944473t

Divide to get

t = 39.2 minutes

3 0
3 years ago
I GIVEEEEEEEEEEE BRAINLIST
irina [24]

Answer:

Step-by-step explanation:

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8 0
3 years ago
What is the solution to the equation 3 + = 4? y = y = y = 1 y = 4
kvv77 [185]

Answer:

y = 1

Step-by-step explanation:

3 + y = 4

y = 1

6 0
3 years ago
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