Question

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Answer 1

x^2−10x+27=0

Step 1: Use quadratic formula with a=1, b=-10, c=27.

x=

−b±√b2−4ac/2a

x= −(−10)±√(−10)2−4(1)(27) /2(1)

x=

10±√−8 /2

Answer:

No real solutions.

Answer 2

$(a-b)^2=a^2-2ab+b^2$

$x^2-10x+27=0\ \ \ \ |-27\\\\x^2-10x=-27\\\\x^2-2\cdot x\cdot5+27=0\ \ \ |+5^2=25\\\\x^2-10x+25=-27+25$