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NARA [144]
3 years ago
14

Convert 1200 second to hours (with calculation)​

Mathematics
1 answer:
IRISSAK [1]3 years ago
3 0
1200 seconds divided by 3600=

0.33333333 of an hour or a third of an hour.

Or just 20 minutes lol
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Vicky drew a scale drawing of a city. She used the scale 1 inch : 2 yards. If the actual width of a neighborhood park is 62 yard
klemol [59]

Answer:

The park is <u>31 inches</u> wide in the drawing.

Step-by-step explanation:

Given:

Vicky drew a scale drawing of a city. She used the scale 1 inch : 2 yards.

The actual width of a neighborhood park is 62 yards.

Now, to find the width of park in drawing.

Let the width of park in drawing be x.

The scale drawing of the city is 1 inch : 2 yards.

So, 1 inch is equivalent to 2 yards.

Thus, x is equivalent to 62 yards.

Now, to get the width of park in drawing by using cross multiplication method:

\frac{1}{2} =\frac{x}{62}

By cross multiplying we get:

62=2x

Dividing both sides by 2 we get:

31=x

x=31\ inches.

Therefore, the park is 31 inches wide in the drawing.

8 0
3 years ago
Write a solvable word problem for: 8 For 7= 56
Flauer [41]

Answer:

ggbgghhdhrhbbdbbrbrhdhdhd

3 0
3 years ago
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How do we find the quadratic equation in standard form with the given roots of -1/3, 5?
Olin [163]
I think this is the answer. Because it doesn’t mention a leading coefficient but it’s a quadratic function so it would be
1(x-1/3)(x-5) and that should be your answer. The simplified version is down below

8 0
3 years ago
Evaluate using P E M D A S 2 x 3 + 4
Juli2301 [7.4K]

Step-by-step explanation:

We would do multiplication first, because of order of operations.

2x3=6

Now we add.

6+4=10

hope it helps! :3

8 0
3 years ago
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Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean
Zinaida [17]

Answer:

E[R] = 99 Ω

\sigma_R = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, E[R] = \frac{a+b}{2}  = \frac{95+103}{2} = \frac{198}{2} = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333

Hence,

The standard deviation of resistance, \sigma_R = \sqrt{V(R)} = \sqrt5.333 = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

z_1 = \frac{102-99}{2.3094} = 1.299

z_2 = \frac{98-99}{2.3094} = -0.433

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0
3 years ago
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