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nikklg [1K]
3 years ago
15

Find the missing angle measure for the triangle. PLSSSSSS HELP

Mathematics
2 answers:
Andrews [41]3 years ago
8 0
It it nfjfncjcjcjcnc 100
slega [8]3 years ago
6 0
50° djebdosnneksjsns
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May I please receive help?
Artyom0805 [142]

4, -1/4 -1,

we can do this simply by

(y2-y1)/(x2-x1)

and simplifying

6 0
3 years ago
What is th eqivalent expression for 4x 2/3
mars1129 [50]
Answer:

x in (-oo:+oo)

(4*x^2)/3 = 0

4/3*x^2 = 0 // : 4/3

x^2 = 0

x = 0

x = 0
6 0
3 years ago
If f(x)=2^x find x if f(x)= 1/4
Sergeeva-Olga [200]

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ f(x)=2^x~\hspace{7em} \begin{cases} f(x)=\cfrac{1}{4} \end{cases} \qquad \qquad \cfrac{1}{4}=2^x\implies \cfrac{1}{2^2}=2^x \\\\\\ 2^{-2}=2^x\implies \stackrel{\textit{if the bases are the same, the exponents must also be the same}}{-2=x}

5 0
3 years ago
Jana knows that in ∆LET and ∆PVC, ET ≅ VC, ∠L ≅ ∠P and ∠E ≅ ∠V. Which congruence postulate or theorem can be used to prove that
LiRa [457]

Answer:

SAA theorem

Step-by-step explanation:

The given data with regards to ΔLET and ΔPVC are;

ET ≅ VC

∠L ≅ ∠P

∠E ≅ ∠V

From the given relationship, we have that two angles and the adjacent (nonincluded) side to the two angles in ΔLET are congruent to the corresponding two angles and adjacent (nonincluded) side of ΔPVC

Therefore, the congruence theorem that can be used to prove that the two triangles are congruent is the Side-Angle-Angle (SAA) congruency theorem

The SAA congruency theorem states that, two triangles that have two angles and a nonincluded side on one triangle being congruent to the corresponding two angles and a non included side on the other triangle, then the two triangles are congruent.

7 0
3 years ago
Which are the correct measures for
-BARSIC- [3]

Answer:

option c is the correct answer

Step-by-step explanation:

∠YXZ+117°=180°

∠YXZ=180°-117°

∠YXZ=63°

63°+36°+∠YZX=180°(sum of angles is 180)

99°+∠YZX=180

∠YZX=180-99

∠YZX=81

5 0
3 years ago
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