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Sauron [17]
3 years ago
6

Really Need help please

Mathematics
2 answers:
Virty [35]3 years ago
7 0
1. Add the total ages up and divide that by the number of volunteers, that gives you 130 as the total ages added up and 10 volunteers, which gives you a mean of 13,
2. When the numbers are put in an ascending order 12 and 13 appear to be the middle two, therefore divide the sum of the two to find the median, which is 12.5.
Lostsunrise [7]3 years ago
6 0

Answer:

See below in BOLD.

Step-by-step explanation:

Rearrange in ascending order of age:

11 11 11 12 12 13 14 15 15 16

1. The mean = (11 +11 +11 +12 +12 +13+ 14 +15+ 15+ 16) / 10

= 130/10

= 13 years.

2.  The median is the mean of the middle 2 numbers in the list:

= (12 + 13) / 2

= 12.5 years.

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Three classes at a junior high school raised money to buy new computers. Ms. Moore’s class raised $249.00. Ms. Aguilar raised $3
Olin [163]

Answer:

The final amount is $1109.81

Step-by-step explanation:

In order to find the total amount, start with the know amount, which is Ms. Moore's class. Her class raised $249. Now we can use that to find the amount from Ms. Aguilar's class.

$249 + $396.62 = $645.62

Now we can use the amount from Ms. Aguilar's class to find the amount from Ms. Barry's class

$645.62 - $430.43 = $215.19

Now we can add the three amounts together to find the total amount.

$249 + $645.62 + $215.19 = $1109.81

3 0
3 years ago
Ava,Carter,Luke and their dad each mow a different section of their yard.Ava mow 1 /12 of the yard, Carter mow 2 /12 of the yard
lubasha [3.4K]
His dad mowed 5/12 of the yard
4 0
3 years ago
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The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
3 years ago
Read 2 more answers
Which shows 34,867 rounded to the nearest hundred? O A 34,900 . B. 34.800 C. 34 500 D. 34.000​
worty [1.4K]

Answer:

A. 34,900

Good Luck!!

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ 

7 0
2 years ago
13+37 please help me!
kherson [118]

Answer:

13+37=50

Step-by-step explanation:

4 0
2 years ago
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