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Yuliya22 [10]
3 years ago
9

Help me with this question

Mathematics
2 answers:
frosja888 [35]3 years ago
7 0

A linear equation in the form y = mx + c has slope m Any line parallel to 3x + 9y = 5 has the same slope 3x + 9y = 5 → 9y = -3x + 5 → y = (-3/9)x + 5/9 → y = -⅓x + 5/9 & So it’s 10 and 0

daser333 [38]3 years ago
7 0
5

Steve’s score has to be -5 because Denias score is positive, leaving her score at 5 because it is the opposite of -5
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Archy [21]

Answer:

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Step-by-step explanation:

please mark brainliest

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3 years ago
Read 2 more answers
If p varies directly as q and q= 70 when p= 10, find q when p = 12
stellarik [79]

\qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\ \textit{\underline{x} varies directly with }\underline{z^5}\qquad \qquad \stackrel{\textit{constant of variation}}{x=\stackrel{\downarrow }{k}z^5~\hfill } \\\\[-0.35em] ~\dotfill

\stackrel{\textit{"p" varies directly as "q"}}{p~~ = ~~kq}\qquad \textit{we also know that} \begin{cases} q=70\\ p=10 \end{cases}\implies 10=k70 \\\\\\ \cfrac{10}{70}=k\implies \cfrac{1}{7}=k\hspace{15em}\boxed{p=\cfrac{1}{7}k} \\\\\\ \textit{when p = 12, what is "q"?}\qquad 12=\cfrac{1}{7}q\implies 12=\cfrac{q}{7}\implies 84=q

5 0
1 year ago
Solve the equation below for x.
svetlana [45]
If x + y = 5 and 3x = 2 then what you
do is:
3x = 2 and since you want the variable by itself you’d divide by 3... giving you an answer of x = 2/3 BUT YOURE NOT DONE YET
so now you plug what x equals (2/3) into the equation x + y = 5:
2/3 + y = 5
to solve this you have to subtract each side by 2/3 so x = 5 - 2/3
(5/1 - 2/3.... to get like denominators multiply the nominator and the denominator for 5/1 by 3 giving you: 15/3 - 2/3 = 13/3)
your final answer would be 13/3
5 0
3 years ago
Would the owners of the company be happier if the slope was steeper or flatter?
marissa [1.9K]
Steeper is better than flatter

7 0
3 years ago
Read 2 more answers
How many integers from 4 to 50 inclusive are neither multiples of 3 nor 4????
puteri [66]

Answer:

24 integers

Step-by-step explanation:

There are (50 - 4)+1 = 47 integers from 4 to 50 INCLUSIVE.

We find the multiples of 3 and find the multiples of 4 and subtract that from the 47 integers to get INTEGERS that are NEITHER multiple of 3 nor 4.

Let's list multiples of 3 (from 4 to 50 inclusive):

6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48

Multiples of 4 (from 4 to 40 inclusive):

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48

From the 2 lists, let's take out the <em>common ones:</em>

<em>THe common ones are 12, 24, 36, 48</em>

<em />

We count all from multiples of 3 list, but don't count the common from multiples of 4's list.

So there are 15 multiples of 3, and 8 multiples of 4

In total 15 + 8 = 23 multiples of 3 and 4

So there are 47 - 23 = 24 integers that are NOT multiples of 3 nor 4

6 0
3 years ago
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