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DiKsa [7]
3 years ago
13

The length of a swimming pool is 8m longer than its width and the area is 1o5m2?

Mathematics
2 answers:
Nina [5.8K]3 years ago
5 0
Let the breadth be x
length=x+8
according to the question
area of the pool = l*b
105=x*x+8
if u solve this equation further u will get the answer
elena55 [62]3 years ago
4 0


length = w + 8 and  width = w and A = 105

A = W* L

105 =w(w + 8)

105 = w² + 8w

0 = w² + 8w - 105

0 = (w + 15)(w -7)

0 = w + 15   or 0 = w -7

w = -15      or   w = 7

width cant be negative, so

w = 7  and L = 7 +8

w = 7 and L = 15

7 * 15 = 105  check 

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ELEN [110]

9514 1404 393

Answer:

  a) BE = 5; DE = 6; EF = 4

  b) ∠EFC ≅ ∠DA.F ≅ ∠BDE  or  <em>b = e = f = i</em>

Step-by-step explanation:

Each short segment is the same length as the marked one it is parallel to.

  E is the midpoint of BC, so BE = EC = 5.

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5 0
3 years ago
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X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

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\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

undefined

6 0
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