Answer:
(- 
, 
)
Step-by-step explanation:
Given the2 equations
6 - 2x = y → (1)
14 + 3x = y → (2)
Substitute y = 14 + 3x into (1)
6 - 2x = 14 + 3x ( subtract 3x from both sides )
6 - 5x = 14 ( subtract 6 from both sides )
- 5x = 8 ( divide both sides by - 5 )
x = -
Substitute x = - into either of the 2 equations for the corresponding value of y
Substituting into (1)
y = 6 - 2(- ) = 
+ 
=
solution is ( - , )
C = 2 pi r given r = 4
so
C = 2 pi (4)
C = 8 pi
answer
C. C = 8pi
(y+3)(y^2-3y+9)
=y(y^2-3y+9)
+3(y^2-3y+9)
=(y^3-3y^2+9y)+(3y^2-9y+27)
=y^3-3y^2+9y+3y^2-9y+27
=y^3+27
Answer:
and the addition will be p+q
Step-by-step explanation:
the diffrence between p and q is u have to add so the answer will be p-q
