Answer:
no
Step-by-step explanation:
Answer:
y=3x.........1
y=x^2-10.......2
substituting value of eq 1 to 2
3x=x^2-10
x^2-10-3x=0
x^2-3x-10=0
x^2-5x+2x-10=0
X(x-5)+2(x-5)=0
(x-5)(X+2)=0
then
X=5 or X=-2
again
y=??
when X=5
y=3×5=15
when X=-2
y=-6
Answer:
First statement: 10 road workers take 5 days to complete a work, working 2 hours a day.
Let us calculate how many days 2 workers will need, if they were to work at the same pace (i.e. each working 2 hours a day). The workforce is now decreased to 2 divided by 10 = 1/5 (i.e. one-fifth).
Therefore proportionately, the time will increase to 5 days divided by 1/5, (i.e. 5 / (1/5) = 25 days.
We now know that 2 workers will need 25 days to finish the work, if they work for 2 hors a day.
Now the question is what will happen if the two people work 5 hours per day, instead of 2 hours per day?
The labor they put in has increased to 5 divided by 2 = 2.5 (i.e. 2 and half times).
Consequently, the time needed to finish the work will decrease to 25 divided by 2.5 (i.e. ( 25 / 2.5 ) = 10. days.
The answer : 10 Days.
Answer:
20/5 = x /4 x = 80/5 = 16
x - 10 / 39 = 5/15 = 1/3
3x - 30 = 39
3x = 69
x = 23
(2x + 10 ) * 4 = 10 *(x + 3)
8x + 40 = 10x + 30
2x = 10
x = 4.
AE = 2(5) + 10 = 20, hope this helped.
Answer:
B and D
Step-by-step explanation:
