Convert 3.5 ⋅ 10^4 to standard form.

Solve for x and then find the measure of ZB

VARVARA [1.3K]

Answer:

Step-by-step explanation:

angle A = angle B (because they are alternate exterior angles)

8x+6=4x+38

8x-4x=38-6

4x=32

x=32/4

x=8

For angle A

8x+6

8*8+6

64+6

70

For angle B

4x+38

4*8+38

32+38

70

8 0

3 years ago

7. for normal situations, the minimum speed limit throughout the u.s. interstate highway system is 72 km/hr which is 45 miles pe

gladu [14]

Answer:

Question 7: Distance = 237.6 km

Question 8: Distance = 399.3 km

Step-by-step explanation:

Question 7:

Given:

Minimum speed (s) = 72 km/hr

Time taken (t) = 3.3 hours.

We know that, distance traveled is equal to the product of speed and time.

Therefore using distance formula, we get:

Distance = Minimum speed × Time

Distance = $s\times t$

Distance = $72\times 3.3 = 237.6\ km$

Therefore, distance traveled at this speed is 237.6 km.

Question 8:

Maximum speed (S) = 121 km/hr

Time taken (T) = 3.3 hours.

We know that, distance traveled is equal to the product of speed and time.

Therefore using distance formula, we get:

Distance = Maximum speed × Time

Distance = $S\times T$

Distance = $121\times 3.3 = 399.3\ km$

Therefore, distance traveled at this speed is 399.3 km.

3 0

3 years ago

Can y'all help me? Please

Marta_Voda [28]

Step-by-step explanation:

lois need to sell 504 pies to get this amount.

6 0

3 years ago

Let the region R be the area enclosed by the function f(x)=ln(x) and g(x)= 1/2x-2. Find the volume of the solid generated when t

Neporo4naja [7]

Answer:

$V=61.66$

Step-by-step explanation:

This problem can be solved by using the expression for the Volume of a solid with the washer method

$V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx$

where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).

Before we have to compute the limits of the integral. We can do that by taking f=g, that is

$f(x)=g(x)\\ln(x)=\frac{1}{2}x-2$

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)

x1=0.14

x2=8.21

and because the revolution is around y=-5 we have

$R=ln(x)-(-5)\\r=\frac{1}{2}x-2-(-5)\\$

and by replacing in the integral we have

$V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\$

$V=\pi [28x+\frac{1}{x}+xln^2x-12xlnx-6lnx]$

and by evaluating in the limits we have

$V=61.66$

Hope this helps

regards

3 0

3 years ago

Last Wednesday it snowed 3 1/4 in. On Sunday it snowed 3 4/5 in. On which day did it snow more? How much more?

damaskus [11]

3 4/5 because when you make the denominators equal by multiplying 1/4 by 5 on both sides and 4/5 by 4 and both sides you will get 5/20 and 16/20

4 0

3 years ago

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