Answer
school building, so the fourth side does not need Fencing. As shown below, one of the sides has length J.‘ (in meters}. Side along school building E (a) Find a function that gives the area A (I) of the playground {in square meters) in
terms or'x. 2 24(15): 320; - 2.x (b) What side length I gives the maximum area that the playground can have? Side length x : [1] meters (c) What is the maximum area that the playground can have? Maximum area: I: square meters
Step-by-step explanation:
325 - [4(58 - 19) + (75 / 3)]
Divide:
325 - [4(58 - 19) + 25]
Distribute 4:
325 - [232 - 76 + 25]
Subtract:
325 - [156 + 25]
Add:
325 - [181]
Subtract:
144
N P r = (n!)/((n-r)!)
8 P 4 = (8!)/((8-4)!)
8 P 4 = (8!)/(4!)
8 P 4 = (8*7*6*5*4!)/(4!)
8 P 4 = 8*7*6*5
8 P 4 = 1680
The final answer is 1680
H=2ft
d=6 ft
r=d/2
r=6/2=3ft
V= π•r^2•h
V=3.14•3^2•2
V=3.14•9•2
V=56.52 ft3
V~56.5ft3
