First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now
2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4
At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.
Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.
For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196
No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.
So x^2 = -4 has no real solutions. Taking the square root of both sides leads to
x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values
Answer:
d) x = 72°
Step-by-step explanation:
Corresponding Angles: The pair of angles formed on the same side of traversal which crosses two parallel lines is called a pair of corresponding angles.
These angles are EQUAL to each other.
Now, here in the given figure:
The two below lines are parallel to each other.
Also, the line crossing it on the right side forms a traversal.
So angle x and angle with 72 degrees form a pair of Corresponding Angles.
⇒ x = 72°
Hence the measure of angle x = 72°
2v=-68 I believe is the answer
Of the four x-coordinates to choose only 1/√(11) belongs can belong to the unit circle.
The other three x-coordinates are greater than 1, then they are out of the unit circle.
The unit circle formula is x^2 +y^2 = 1
Then to find the y-coordinate given the x-coordinate you can solve for y from that formula:
y^2 = 1 - x^2
y = (+/-)√(1-x^2)
Substitute the value of x
y = (+/-)√{1 - [1/√(11)]^2} = (+/-) √{(1 - 1/11} =(+/-) √ {(11 -1)/11 =(+/-)√(10/11) ≈ +/- 0.95
21 goes into 76 3 times with a remainder of 8 left
