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andreyandreev [35.5K]
3 years ago
15

Use the unit circle to find the inverse function value in degrees cos^-1 (sqrt3/2)

Mathematics
1 answer:
Marina CMI [18]3 years ago
3 0
Better to write that as:

       -1
cos      [ sqrt(3) / 2 ]

since the cosine is defined as "adjacent side over hypotenuse,"  we know that the adj. side is sqrt(3) and that the hyp is 2.    The primary solution will be in Quadrant I because the adj. side is positive.

Think:  which angle in Q I has adj. side equal to sqrt(3) and hyp equal to 2?

That'd be 30 degrees.  Unfortunately, that's not one of your answer choices.  Thus, reflect that angle in the positive x-axis; you'll end up with a ray whose positive angle is 330 degrees. 

I'd suggest you ensure that you've copied this problem down correctly.
                                                                 sqrt(3)
Did you mean sqrt(3/2) or did you mean ----------  ?? 
                                                                     2
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Grace starts with 100 milligrams of a radioactive substance. The amount of the
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Answer:

100 is grace's initial amount. w is how much of the substance is being decrased each week. in ryan's equation, 1 is 100% of the substance, so the initial amount, and 0.4 is the amount that is being decreased.

Step-by-step explanation:

8 0
3 years ago
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3 years ago
Determine the inverse of the function f (x) = 4(x − 3)2 + 2. inverse of f of x is equal to 3 minus the square root of the quanti
Elodia [21]

The inverse of the function f(x)  = 4(x-3)² + 2 is f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

The given function is:

f(x)   =  4(x  - 3)²  +  2

To find the inverse of the function:

Make x as the subject of the formula

4(x-3)^2 = f(x) - 2\\(x-3)^2 = \frac{f(x)-2}{4} \\x - 3 = \sqrt{\frac{f(x)-2}{4} } \\x = \sqrt{\frac{f(x)-2}{4} } + 3

Replace x by f^{-1}(x) and replace f(x) by x

f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

Therefore, the inverse of the function is:

f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

Learn more here: brainly.com/question/17285960

4 0
2 years ago
What is the difference, in hours and minutes, between these times?<br>a)11:25 and 14:10​
lutik1710 [3]

Answer:

14:10 is 24 hours clock which only come in after noon that is 12

11:25 is a normal clock with remains normal before 12:00

8 0
3 years ago
What is the distance between (10, 6) and (-2, -3)
Helga [31]

Answer:

15 units.

Step-by-step explanation:

The distance between the points (x1, y1) and (x2, y2) is

√(x1-y1)^2 + (y1-y2)^2))

So here it is:

√(10- -2)^2 + (6- -3)^2)

= √(144+81)

=  √225

= 15.

4 0
3 years ago
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