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vlabodo [156]
3 years ago
5

Match each correlation coefficient with the type of association it indicates between the variables x and y.

Mathematics
2 answers:
Artemon [7]3 years ago
7 0

r = 0.9 (a strong linear association in which y increases as x increases)

r = -1.0 (a perfect linear association in which y decreases as x increases)

r = -0.6 (a moderate linear association in which y decreases as x increases)

r = 0.1 (no linear association or a very weak association)

ser-zykov [4K]3 years ago
5 0
R = 0.9
A value of 0.9 would indicate that the correlation is positive. Since it's also close to the value 1, it would also tell us that the correlation of y and x is strong. Therefore, r = 0.9 would be a strong linear association in which y increases as x increases.

r = -1.0
Since the value of r is negative, this would mean that the correlation is also negative. Furthermore, the value of r is also at the minimum point which is -1.0 thus this would tell us that the correlation is a perfect linear association in which y decreases as x increases.

r = -0.6
Likewise, this r value is also negative thus allowing us to know that y will decrease as x increases. The value of r, which is -0.6, is also close to -1.0. This allows us to tell that it is a strong relationship. Therefore, r = -0.6 is a strong linear association in which y decreases as x increases.

r = 0.1
For this correlation, the r value is positive. This would indicate that the value of y will increase as x increases. Since the r value is only 0.1, we cannot say that it is a strong relationship since it is far from the maximum value for a perfect relationship which is 1. Therefore, r = 0.1 is a moderate linear association in which y increases as x increases.
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Step-by-step explanation:

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x = 4 is NOT a solution to both inequalites.

Part c) Find another value of x that is a solution to both inequalities.

<u>solving -2x < 10</u>

-2x\:

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\left(-2x\right)\left(-1\right)>10\left(-1\right)

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<u>solving -6 < -2x</u>

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switch sides

-2x>-6

Multiply both sides by -1 (reverses the inequality)

\left(-2x\right)\left(-1\right)

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<h3>SUBSTITUTING x = 1</h3>

FOR  -2x < 10

substituting x = 1 in -2x < 10

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TRUE!

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substituting x = 1 in -6 < -2x

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-6 < -2

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