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emmainna [20.7K]
2 years ago
15

What is the perimeter of a regular heptagon with a side length of 9 inches?

Mathematics
1 answer:
jok3333 [9.3K]2 years ago
6 0
What kind of Question is that. That is some real math right there.
You might be interested in
Can someone plz help me
Illusion [34]
First rectangle:
Has 3 cubes in each 5 layers, and imagine it, so we have all dimension needed which is:
l=3 unit
w=1 unit
h=5 unit.
V=l×w×h
V=3×1×5
V=15 cubic inches.

Second rectangular:
Doing the same like that to get:
l=5 unit
w=1 unit
h=3 unit
V=15 cubic inches. As a result, there are no prism that are greater to each other, which mean that they have the same volume of 15 cubic inches. Hope it help!
6 0
3 years ago
Use the sum and difference identities to find the exact values of the sine, cosine, and tangent of the angle. . 165 = 135 + 30
Serhud [2]
So lets get to the problem 

<span>165°= 135° +30° </span>

<span>To make it easier I'm going to write the same thing like this </span>
<span>165°= 90° + 45°+30° </span>

<span>Sin165° </span>
<span>= Sin ( 90° + 45°+30° ) </span>
<span>= Cos( 45°+30° )..... (∵ Sin(90 + θ)=cosθ </span>
<span>= Cos45°Cos30° - Sin45°Sin30° </span>

<span>Cos165° </span>
<span>= Cos ( 90° + 45°+30° ) </span>
<span>= -Sin( 45°+30° )..... (∵Cos(90 + θ)=-Sinθ </span>
<span>= Sin45°Cos30° + Cos45°Sin30° </span>


<span>Tan165° </span>
<span>= Tan ( 90° + 45°+30° ) </span>
<span>= -Cot( 45°+30° )..... (∵Cot(90 + θ)=-Tanθ </span>
<span>= -1/tan(45°+30°) </span>
<span>= -[1-tan45°.Tan30°]/[tan45°+Tan30°] </span>

<span>Substitute the above values with the following... These should be memorized </span>
<span>Sin 30° = 1/2 </span>
<span>Cos 30° =[Sqrt(3)]/2 </span>
<span>Tan 30° = 1/[Sqrt(3)] </span>
<span>Sin45°=Cos45°=1/[Sqrt(2)] </span>
<span>Tan 45° = 1</span>
4 0
3 years ago
If f(x) = 3x 7, find f(a - 1) a. 3a 6 b. 3a 4 c. 3a 8 d. 3a 10
Rom4ik [11]
Hello,

Let's suppose f(x)=3x+7
f(a-1)=3(a-1)+7=3a-3+7=3x+4
Answer B with a sign "++++++++++++++++++++++++++++"


5 0
3 years ago
What is the value of x in units
nikdorinn [45]

\triangle RQT\ \text{and}\ \triangle SRT\ \text{are similar. Therefore the sides are in proportion.}\\\\\dfrac{RT}{TQ}=\dfrac{TS}{RT}\\\\\text{We have}\ RT=x,\ TQ=16,\ TS=9.\ \text{Substitute:}\\\\\dfrac{x}{16}=\dfrac{9}{x}\qquad\text{cross multiply}\\\\x^2=(9)(16)\\\\x^2=144\to x=\sqrt{144}\\\\\boxed{x=12}

6 0
3 years ago
Read 2 more answers
5,4,5.5,4.5 and 5.5. What is the mean distance
Anit [1.1K]
The mean distance is 4.9
8 0
3 years ago
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