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Kay [80]
3 years ago
14

Please help me I don't understand how I do this

Mathematics
1 answer:
pishuonlain [190]3 years ago
5 0

29/2 ÷ 5/4

2/29 × 5/4

<em>To</em><em> </em><em>get</em><em> </em><em>your</em><em> </em><em>answer</em><em> </em><em>its</em><em> </em><em>just </em><em>a</em><em> </em><em>matter</em><em> </em><em>of</em><em> </em><em>under</em><em>standing</em><em> </em><em>the</em><em> </em><em>qu</em><em>estion</em><em>,</em><em> </em><em>they</em><em> </em><em>are</em><em> </em><em>asking</em><em> </em><em>you</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>how</em><em> </em><em>many</em><em> </em><em>1</em><em>¼</em><em> </em><em>gallons</em><em> </em><em>of</em><em> </em><em>water</em><em> </em><em>can</em><em> </em><em>fit</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>tank</em><em> </em><em>that</em><em> </em><em>can</em><em> </em><em>hold </em><em>1</em><em>4</em><em>½</em><em> </em><em>gallons</em><em> </em><em>of</em><em> </em><em>water</em><em> </em><em>so</em><em>,</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>answer</em><em> </em><em>we</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>divid</em><em>e</em><em> </em><em>1</em><em>4</em><em>½</em><em> </em><em>by</em><em> </em><em>1</em><em>¼</em><em> </em><em>(</em><em> </em><em>these</em><em> </em><em>fractions</em><em> </em><em>are </em><em>mixed</em><em> </em><em>numbers</em><em> </em><em>so</em><em>,</em><em> </em><em>you</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>change </em><em>them</em><em> </em><em>into</em><em> </em><em>improper</em><em> </em><em>fraction</em><em>)</em>

<em>Now</em><em> </em><em>when</em><em> </em><em>dividing</em><em> </em><em>the</em><em> </em><em>fractions</em><em> </em><em>you</em><em> </em><em>always</em><em> </em><em>invert</em><em> </em><em>the</em><em> </em><em>fraction</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>left</em><em> </em><em>side</em><em> </em><em>and</em><em> </em><em>the</em><em> </em><em>division </em><em>sign</em><em> </em><em>turns</em><em> </em><em>into</em><em> </em><em>a</em><em> </em><em>multiplication</em><em> </em><em>sign</em><em>.</em><em>.</em><em>.</em>

<em>2</em><em>9</em><em>/</em><em>2</em><em>÷</em><em>5</em><em>/</em><em>4</em><em> </em><em>=</em><em> </em><em>2</em><em>/</em><em>2</em><em>9</em><em>×</em><em>5</em><em>/</em><em>4</em><em>.</em>

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The "o" in (fog) is a stand-in for the "ring operator" (∘) which is the operator used to signify a composition. A composition is evaluated right-to-left. That means (f∘g)(x) ≡ f(g(x)). The value of g(x) is found first, and is operated on by the function f.

Writing the composition in the form f(g(x)) lets you identify the layers of parentheses. As with any expression evaluation, the Order of Operations applies. It tells you to evaluate the expression in the innermost parentheses and work your way out.

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To evaluate (f∘g)(-2) = f(g(-2)), we must first evaluate g(-2). That is ...

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Now that we know g(-2) = -6, we know this expression is ...

  f(-6) = 8 -10(-6) = 8 +60 = 68 . . . . . substitute for x in 8-10x

Then the value we're looking for is ...

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