Osmotic pressure is the pressure that would have to be applied to a pure solvent to prevent it from passing into a given solution by osmosis.
That can be mathematical computed from the expression:
Osmotic pressure=C×R×T
Where,
C= Concentration
R=Gas constant
T=Temperature
Concentration=Number of moles of solute/Volume(L)
=0.005*1000/100
=0.05
R= 0.08206 atm L/mol K
T=25+273
=298
Osmotic pressure= 0.05×0.08206×298
=1.2 atm
The total heat of hydration of 1. 00 mol of gas phase
ions and
ions is - 684 kJ/mol.
Calculation ,
Given data ,
Heat of solution = 17. 2 kJ/mol
lattice energy of KCl(s) = 701. 2 kJ/mol.
heat of hydration = ?
The KCl is formed by
ions and
– ions
Δ
= U° + Δ
Δ
= Δ
- U° = 17. 2 kJ/mol - 701. 2 kJ/mol = - 684 kJ/mol
Hence, heat of hydration of 1. 00 mol of gas phase
ions and
ions is - 684 kJ/mol.
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Answer:
Dissociation of O-H bond is highly favorable in p-cyanobenzoic acid resulting to higher acidity as compared to m-cyanobenzoic acid.
Explanation:
In p-cyanobenzoic acid, adjacent carbon to carboxyl group (-COOH) gets a partial positive charge due to electron withdrawing resonating effect of carboxyl group as compared to m-cyanobenzoic acid.
Due to this partial positive charge on carbon atom in p-cyanobenzoic acid, O-H bond in -COOH group remains highly polarized towards oxygen atom. Hence, dissociation of O-H bond is highly favorable in p-cyanobenzoic acid resulting to higher acidity as compared to m-cyanobenzoic acid.
Resonance structures are given below.
Answer:
To calculate electronegativy, find the electronegative values of each element involved in the bond. Once you know those values, subtract the higher from the lower to determine the electronegative difference.
Explanation:
Obtain an electronegativity value chart
Every element on the periodic table has a set electronegativity; these charts are easily obtainable through the Internet or a general chemistry textbook. Electronegativity is the ability of an element to attract electrons towards itself.
Determine the electronegativity of the individual elements in the bond
Using the table obtained in step one, find the electronegative value of each element. On the periodic table, electronegativity increases from left to right along a period and decreases as you go down a group.
Determine the electronegative difference between the two elements
Subtract the smaller electronegative value obtained from the larger electronegative value. This positive value is the electronegative difference for the bond. A larger electronegative difference represents a polar bond in which the sharing of electrons is unequal.
Use the electronegative difference to determine the type of bond
The closer the electronegative difference is to zero, the less polar a bond is. An electronegative difference of zero represents a nonpolar bond. A value between zero and two represents a polar covalent bond. A value greater than two represents an ionic bond. Fluorine is the most electronegative element, with an electronegativity of 4.0.
Answer : The average speed of the object is, 10 m/s
Solution : Given,
Distance traveled by the object = 60 m
Time taken = 6 s
Average speed : It is defined as the distance traveled by an object in per unit time. The unit of average speed is, meter/second.
Formula used :

Now put all the given values in this formula, we get the average speed of an object.

Therefore, the average speed of the object is, 10 m/s