Answer : The number of moles present in ammonia is, 70.459 moles.
Solution : Given,
Mass of ammonia = 
Molar mass of ammonia = 17.031 g/mole
Formula used :
Therefore, the number of moles present in ammonia is, 70.459 moles.
Answer:
C. 0.4.
Explanation:
<em>∵ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) = (no. of moles acetic acid)/(no. of moles of acetic acid + no. of moles of water).</em>
<em></em>
- no. of moles of acetic acid = 2, no. of moles of water = 3.
- Total no. of moles = no. of moles of acetic acid + no. of moles of water = 2 + 3 = 5.
<em>∴ mole fraction of acetic acid (X acetic acid) = (no. of moles acetic acid)/(total no. of moles) =</em> (2)/(5)<em> = 0.4.</em>
Answer:
Choice A: approximately 
.
Explanation:
Note that the unit of concentration, 
, typically refers to moles per liter (that is: 
.)
On the other hand, the volume of the two solutions in this question are apparently given in 
, which is the same as 
(that is: 
.) Convert the unit of volume to liters:
.
.
Calculate the number of moles of 
formula units in that 
of the 
solution:
.
Note that (sulfuric acid) is a diprotic acid. When one mole of completely dissolves in water, two moles of 
ions will be released.
On the other hand, 
(sodium hydroxide) is a monoprotic base. When one mole of formula units completely dissolve in water, only one mole of 
ions will be released.
ions and ions neutralize each other at a one-to-one ratio. Therefore, when one mole of the diprotic acid dissolves in water completely, it will take two moles of to neutralize that two moles of produced. On the other hand, two moles formula units of the monoprotic base will be required to produce that two moles of . Therefore, and formula units would neutralize each other at a two-to-one ratio.
.
.
Previous calculations show that 
of was produced. Calculate the number of moles of formula units required to neutralize that
.
Calculate the concentration of a 
solution that contains exactly 
of formula units:
.
