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3 years ago

How do you find electronegativity

2 answers:

5 0

The higher the attraction for an electron, the higher the electronegativity. It increases as you move left to right and down to up on the periodic table.

Anastaziya [24]3 years ago

4 0

Answer:

To calculate electronegativy, find the electronegative values of each element involved in the bond. Once you know those values, subtract the higher from the lower to determine the electronegative difference.

Explanation:

Obtain an electronegativity value chart

Every element on the periodic table has a set electronegativity; these charts are easily obtainable through the Internet or a general chemistry textbook. Electronegativity is the ability of an element to attract electrons towards itself.

Determine the electronegativity of the individual elements in the bond

Using the table obtained in step one, find the electronegative value of each element. On the periodic table, electronegativity increases from left to right along a period and decreases as you go down a group.

Determine the electronegative difference between the two elements

Subtract the smaller electronegative value obtained from the larger electronegative value. This positive value is the electronegative difference for the bond. A larger electronegative difference represents a polar bond in which the sharing of electrons is unequal.

Use the electronegative difference to determine the type of bond

The closer the electronegative difference is to zero, the less polar a bond is. An electronegative difference of zero represents a nonpolar bond. A value between zero and two represents a polar covalent bond. A value greater than two represents an ionic bond. Fluorine is the most electronegative element, with an electronegativity of 4.0.

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If the initial [NO2] is 0.260 M, it will take ________ s for the concentration to drop to 0.150 M. If the initial is 0.260 , it

Nitella [24]

The question is incomplete, here is the complete question:

At elevated temperature, nitrogen dioxide decomposes to nitrogen oxide and oxygen gas

$NO_2\rightarrow NO+\frac{1}{2}O_2$

The reaction is second order for $NO_2$ with a rate constant of $0.543M^{-1}s^{-1}$ at 300°C. If the initial [NO₂] is 0.260 M, it will take ________ s for the concentration to drop to 0.150 M

a) 1.01 b) 5.19 c) 0.299 d) 0.0880 e) 3.34

<u>Answer:</u> The time taken is 5.19 seconds

<u>Explanation:</u>

The integrated rate law equation for second order reaction follows:

$k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)$

where,

k = rate constant = $0.543M^{-1}s^{-1}$

t = time taken = ?

[A] = concentration of substance after time 't' = 0.150 M

$[A]_o$ = Initial concentration = 0.260 M

Putting values in above equation, we get:

$0.543=\frac{1}{t}\left (\frac{1}{(0.150)}-\frac{1}{(0.260)}\right)\\\\t=5.19s$

Hence, the time taken is 5.19 seconds

6 0

3 years ago

How do atoms form ions

Cerrena [4.2K]

Ions are electrically charged particles formed when atoms lose or gain electrons. They have the same electronic structures as noble gases. Metal atoms form positive ions, while non-metal atoms form negative ions. The strong electrostatic forces of attraction between oppositely charged ions are called ionic bonds.

5 0

3 years ago

(a) The original value of the reaction quotient, Qc, for the reaction of H2(g) and I2(g) to form HI(g) (before any reactions tak

Taya2010 [7]

Answer:

Here's what I get

Explanation:

Assume the initial concentrations of H₂ and I₂ are 0.030 and 0.015 mol·L⁻¹, respectively.

We must calculate the initial concentration of HI.

1. We will need a chemical equation with concentrations, so let's gather all the information in one place.

H₂ + I₂ ⇌ 2HI

I/mol·L⁻¹: 0.30 0.15 x

2. Calculate the concentration of HI

$Q_{\text{c}} = \dfrac{\text{[HI]}^{2}} {\text{[H$_{2}$][I$_{2}$]}} =\dfrac{x^{2}}{0.30 \times 0.15} = 5.56\\\\x^{2} = 0.30 \times 0.15 \times 5.56 = 0.250\\x = \sqrt{0.250} = \textbf{0.50 mol/L}\\\text{The initial concentration of HI is $\large \boxed{\textbf{0.50 mol/L}}$}$

3. Plot the initial points

The graph below shows the initial concentrations plotted on the vertical axis.

7 0

3 years ago

A galvanic cell generates a cell potential of 0.32V when operated under standard conditions according to the reaction above. Whi

Ugo [173]

The complete question is shown in the image attached to this answer.

Answer:

Explanation:

Let us quickly remember that the EMF of a cell under non standard conditions in given by the Nernst equation.

This equation states that;

E = E°cell - 0.592/n log Q

Where

E = EMF under non standard conditions

E°cell= standard EMF of the cell

n = number of electrons transferred

Q = reaction quotient

If the reaction quotient is greater than 1 then cell potential is less than the standard cell potential.

The cell that generates the lowest cell potential is the cell depicted in option C because Q has the greatest positive value(Q<1).

6 0

3 years ago

There are 3 different possible structures (known as isomers) for a dibromoethene molecule, C2H2Br2. One of them has no net dipol

nevsk [136]

Explanation:

Compounds having same molecular formula but different structural and spatial arrangement are isomers.

Three isomers are possible for dibromomethene.

In one structure (IUPAC name: 1,1-dibromomethene), both the bromine atoms are attached to one carbon atom.

In another two structures (Cis and trans), two bromine atoms are attached to two different carbon atoms.

In Cis 1,2-dibromomethene, two bromine atoms are present on the same side.

Whereas in Cis 1,2-dibromomethene, two bromine atoms are present on the opposite side and hence, does not have net dipole moment.

5 0

3 years ago