Collinearity occurs when a few of the independent variables are related or match up. Collinearity increases the large proportion the variance of an estimated regression coefficient which leads to certain regression coefficient having wrong signs. It is used to explain the relationship between two variables.

3 0

3 years ago

What is a fraction box

vichka [17]

I don't know exactly what a fraction box is sorry

3 0

3 years ago

M+1 3/8=5 What does m equal?

Arte-miy333 [17]

$\text{ The value of m is equal to 3.625 or }\frac{29}{8} \text{ or } 3\frac{5}{8}$

Solution:

Given that we have to find the value of "m"

Given expression is:

$m + 1\frac{3}{8} = 5$

Let us first convert the mixed fraction to improper fraction

Steps to follow:

Divide the numerator by the denominator.

Write down the whole number answer.

Then write down any remainder above the denominator.

Therefore,

$1\frac{3}{8}=\frac{8 \times 1+3}{8} = \frac{8+3}{8} = \frac{11}{8}$

Now the expression becomes,

$m + \frac{11}{8} = 5$

Keep the variable "m" on L.H.S and move the constant to R.H.S

$m = 5 - \frac{11}{8}\\\\m = \frac{5 \times 8 -11}{8}\\\\m = \frac{40-11}{8}\\\\m = \frac{29}{8}\\\\\text{In mixed fractions, we can write as }\\\\m = \frac{29}{8} = 3\frac{5}{8}$

Thus value of m is equal to 3.625 or $\frac{29}{8} \text{ or } 3\frac{5}{8}$

3 0

3 years ago

A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from thi

SVETLANKA909090 [29]

Complete question:

Consider a class of 20 students consisting of 5 sophomores, 8 juniors, and 7 seniors. A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from this class, keeping track (in order) of the level of the student that he gets.

1a. How many possible outcomes are in the sample space S? (An outcome is a 5- tuple of students.)

Let A2 denote the event that exactly 2 of the selected students are sophomore, A5 denote the event that exactly 5 of the selected students are the juniors, and A4 denote the event that exactly 4 of the selected students are seniors.

1b. Find the probabilities of each of these three events. A2, A5, A4

1c. Do the events A2, A5, A4 constitute a partition of the sample space?

Answer:

Given:

n = 20

a) The possible outcome in the sample space,S, =

ⁿCₓ = ²⁰C₅

$= \frac{20!}{(20-5)! 5!)}$