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iren [92.7K]
3 years ago
9

I have a questions does any take the 3 chapter test about math if any one please say yes in the comments below

Mathematics
1 answer:
Anastaziya [24]3 years ago
3 0
What? Not everybody has the same math book, try asking someone in your school
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Use the area to find the radius. If you could include steps that’ll be very helpful :)
igor_vitrenko [27]

Answer:

Area = PI * radius^2

radius^2 = Area / PI

radius^2 = 169*PI/PI

radius^2 = 169

radius = 13

Step-by-step explanation:

5 0
3 years ago
Help!
Andru [333]

Answer:

21 Students played string instruments

Step-by-step explanation:

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6 0
3 years ago
Lorenzo is planning a 285-mile trip. His car’s EPA rating is 18 mpg. The number of gallons of gas that Lorenzo will need for the
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It would require 15.8333333 to make that trip.
7 0
4 years ago
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Find the area of triangle ABC with vertices A(2,1), B (12,2), C (12,8). Hence, or otherwise find the perpendicular distance from
Lapatulllka [165]
<h2>The area of a triangle is =54 square units</h2><h2>The perpendicular distance from B to AC is = \frac{108}{\sqrt{149} } units</h2>

Step-by-step explanation:

Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)

x_1=2,y_1=1,x_2=12,y_2=2,x_3=12 and      y_3=8

The area of a triangle is= \frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]

=|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|

=|-54| = 54 square units

The length of AC = \sqrt{(x_1-x_3)^{2} +(y_1-y_3)^2}

                          = \sqrt{(2-12)^{2} +(1-8)^2}

                         =\sqrt{149} units

Let the perpendicular distance from B to AC be = x

According To Problem

\frac{1}{2} \times  x \times \sqrt{149} = 54

⇔x =\frac{108}{\sqrt{149} } units

Therefore the perpendicular distance from B to AC is = \frac{108}{\sqrt{149} } units

5 0
3 years ago
A bicyclist goes 43.54 miles in 3.5 hours. What was her speed?
expeople1 [14]
All you have to do is divided 43.54 divided by 3.5 which is 12.44 mph
6 0
3 years ago
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