The function represents a reflection of f(x) = 5(0.8)x across the x-axis is f(x) = -5(0.8)^x
<h3>Reflection of functions and coordinates</h3>
Images that are reflected are mirror images of each other. When a point is reflected across the line y = x, the x-coordinates and y-coordinates change their position. In a similar manner, when a point is reflected across the line y = -x, the coordinates <u>changes position but are negated.</u>
Given the exponential function below
f(x) = 5(0.8)^x
If the function f(x) is reflected over the x-axis, the resulting function will be
-f(x)
This means that we are going to negate the function f(x) as shown;
f(x) = -5(0.8)^x
Hence the function represents a reflection of f(x) = 5(0.8)x across the x-axis is f(x) = -5(0.8)^x
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Arcsin x + arcsin 2x = π/3
arcsin 2x = π/3 - arcsin x
sin[arcsin 2x] = sin[π/3 - arcsin x] (remember the left side is like sin(a-b)
2x = sinπ/3 cos(arcsin x)-cosπ/3 sin(arc sinx)
2x = √3/2 . cos(arcsin x) - (1/2)x)
but cos(arcsin x) = √(1-x²)===>2x = √3/2 .√(1-x²) - (1/2)x)
Reduce to same denominator:
(4x) = √3 .√(1-x²) - (x)===>5x = √3 .√(1-x²)
Square both sides==> 25x²=3(1-x²)
28 x² = 3 & x² = 3/28 & x =√(3/28)
Minus m-n = 36 so 36 is your answer.
The figure is a trapezoid (or trapezium), and the exact length of the trapezoid is 5 units
<h3>How to determine the length?</h3>
The figure is a trapezoid with the following parameters:
Area = 107.95
Base= 12
Height = 12.7
Length = x
The area of a trapezoid is:
Area = 0.5 * (Base + Length) * Height
So, we have:
0.5 * (12 + Length) * 12.7 = 107.95
Evaluate the product
(12 + Length) * 6.35 = 107.95
Divide both sides by 6.35
12 + Length = 17
Subtract 12 from both sides
Length = 5
Hence, the length of the trapezoid is 5 units
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