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2 years ago

6

What is 6 3/5 Write your answer as a mixed number.

2 answers:

horsena [70]2 years ago

6 0

$\huge\color{navy}{ \tt{6×\frac{3}{5}}}$

$\huge\color{purple}{ \tt{\frac{6}{1}×\frac{3}{5}}}$

$\huge\color{pink}{ \tt{\frac{18}{5}}}$

$\huge\color{gold}{ \tt{3\frac{3}{5}}}$

galina1969 [7]2 years ago

4 0

Answer:

33/5

Step-by-step explanation:

6 3/5 = 33/5

6 x 5 = 30

30 + 3 = 33

33/5.

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3 years ago

Consider the following set of vectors. v1 = 0 0 0 1 , v2 = 0 0 3 1 , v3 = 0 4 3 1 , v4 = 8 4 3 1 Let v1, v2, v3, and v4 be (colu

Alona [7]

Answer:

We have the equation

$c_1\left[\begin{array}{c}0\\0\\0\\1\end{array}\right] +c_2\left[\begin{array}{c}0\\0\\3\\1\end{array}\right] +c_3\left[\begin{array}{c}0\\4\\3\\1\end{array}\right] +c_4\left[\begin{array}{c}8\\4\\3\\1\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right]$

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$\left[\begin{array}{cccc}0&0&0&8\\0&0&4&4\\0&3&3&3\\1&1&1&1\end{array}\right]$

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$\left[\begin{array}{cccc}1&1&1&1\\0&3&3&3\\0&0&4&4\\0&0&0&8\end{array}\right]$

This matrix is in echelon form. Then, now we apply backward substitution:

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$8c_4=0\\c_4=0$

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$4c_3+4c_4=0\\4c_3+4*0=0\\c_3=0$

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$3c_2+3c_3+3c_4=0\\3c_2+3*0+3*0=0\\c_2=0$

4.

$c_1+c_2+c_3+c_4=0\\c_1+0+0+0=0\\c_1=0$

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4 0

3 years ago

loris [4]

Answer:

Cos x = $\frac{base}{hypotenuse}=\frac{\sqrt{3} }{2}$

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Step-by-step explanation:

Sin x = $\frac{perpendicular}{hypotenuse} = \frac{1}{2}$

So, Perp = 1 and hyp = 2

<em>Putting this in Pythagorean theorem to get the base</em>

$c^2 = a^2+b^2$

$a^2 = c^2-b^2$

base ² = 4-1

base² = 3

<em>Taking square root on both sides</em>

Base = $\sqrt{3}$

Now

Cos x = $\frac{base}{hypotenuse}=\frac{\sqrt{3} }{2}$

Tan x = $\frac{perpendicular}{base} = \frac{1}{\sqrt{3} }$

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3 years ago

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LekaFEV [45]

Answer:

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$c=\sqrt{720}$

$c=12\sqrt{5}$

$c=26.83281$

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3 years ago

Read 2 more answers