Answer:
See below in bold.
Step-by-step explanation:
For the fair coin Prob(head) = 1/2 and Prob(Tail) = 1/2.
For the biased coin it is Prob(head) = 2/3 and Prob(Tail) = 1/3.
a) Prob(2 heads) = 1/2 * 2/3 = 1/3.
b) Prob(2 tails) = 1/2 * 1/3 = 1/6.
c) Prob(1 head ) = Prob(H T or T H) = 1/2 * 1/3 + 1/2 * 2/3) = 1/6+1/3 = 1/2.
d) Prob (at least one head) = prob (HH or TH or HT) = 1/3 + 1/2 =<em> </em>5/6.
A ratio is a one or more letter term
The answer is -3 because you’re plugging g(x) into f(x). For every x there is in f(x), plug in g(x)’s equation. After you get another equation (simplified), which is x^2 -7x -11, plug -1 for every x and condense.
All the numbers in this range can be written as

with

and

. Construct a table like so (see attached; apparently the environment for constructing tables isn't supported on this site...)
so that each entry in the table corresponds to the sum of the tens digit (row) and the ones digit (column). Now, you want to find the numbers whose digits add to perfect squares, which occurs when the sum of the digits is either of 1, 4, 9, or 16. You'll notice that this happens along some diagonals.
For each number that occupies an entire diagonal in the table, it's easy to see that that number

shows up

times in the table, so there is one instance of 1, four of 4, and nine of 9. Meanwhile, 16 shows up only twice due to the constraints of the table.
So there are 16 instances of two digit numbers between 10 and 92 whose digits add to perfect squares.
There are 9 two-year-olds and 18 each of 3 and 4 year olds.
To solve this we could write and solve the equation below, letting x be the number of 3 and 4 year olds.
x/2 + x + x = 45
x + 2x + 2x = 90
5x = 90
x = 18
From here, we just divide 18 by 2 to get the number of 2 year olds.