Answer:
Check the explanation
Explanation:
An integer (int) is of two different bytes and each page has 200 bytes in length. What this means is that each row of array A (100 int) will fits perfectly in a page.
(a) For the initial or first array-initialization loop, one column is processed at a time, so a page fault will be generated at every inner loop iteration, with a total of 100*100=10,000 page faults.
(b) And when it comes to the second array-initialization loop, one row is processed at a time, and a page fault is generated at every outer loop iteration, with a total of 100 page faults.
Hence second array-initialization loop, has better spatial locality.
When someone may be giving away something for free.
Answer:
No you can not tell that recursion is ever required to solve a problem.
Recursion is required when in the problem, the solution of the input depends on the solution of the subsets of the input.
Iteration is also another form of repetitive approach we follow to solve that kind of problems.
But the difference between recursion and iteration is :
- In recursion we call the function repeatedly to return the result to next level.
- In iteration certain bunch of instructions in a loop are executed until certain conditions met.
Explanation:
For example in the Fibonacci sequence problem, to find
, we need to compute
and
before that.
- In case of recursion we just call the method Fibonacci(n) repeatedly only changing the parameter Fibonacci(n-1), that calculates the value and return it.
Fibonacci(n)
1. if(n==0 or n==1)
2. return 1.
3.else
4. return( Fibonacci(n-1)+Fibonacci(n-1) )
- But in case of iteration we run a loop for i=2 to n, within which we add the value of current
and
to find the value of 
Fibonacci(n)
1. if(n<=2)
2. result = 1
3. else
4. result1 =1 and result2=1.
5. { result = result1 +result2.
6. result1= result2.
7. result2 = result.
8. }
9. output result.
Answer:
Explanation:
Let's do this in Python, first we need to convert the number into string in order to break it into a list of character, then we can replace the kth character with d. Finally we join all characters together, convert it to integer then output it
def setKthDigit(n, k, d):
n_string = str(n)
d_char = str(d)
n_char = [c for c in n_string]
n_char[k] = d_char
new_n_string = ''.join(n_char)
return int(new_n_string)