Answer:
a. 100%
b. 50%
c. 66.6%
Explanation:
a.
The memory references D6, 58, D8, 9A, DE and 5C all results in misses and the miss ratio is 100 (that is , 6 misses/ 6 references*100 = 100%)
b.
If fully associative cache is used, there will be a 3 cache misses with miss ratio of (3/6*100) = 50%.
c.
With a 2-way set-associative cache, 4 memory reference misses will occur, with a miss ratio of (4/6*100)= 66.6% misses.
roster[50] is an array of "students", so roster[9] is a "student". Therefore, roster[9].name is a string.
Answer:
create the integer variable and initialize it to one, with the do statement, increment the variable by one and print it, then the while statement checks if the variable is less than or equal to 10.
#include <iostream>
using namespace std;
int main(){
int i = 1;
do {
cout<< i << "\n";
i++;
}
while (i <= 10);
}
Explanation:
The C++ source code initializes the integer variable i to one and increments and print the value if the value is less than or equal to ten. The do-while statement executes a block of code before the condition is implemented.
Explanation:
Format the text in Small caps. Manually replace the lowercase letters with uppercase letters.
