Answer:A)35choices
B)475,020choices
C)132choices
D)0.000278
E)0.000166
Step-by-step explanation:
Given 7poultry items represented by 7p
10 red meat items=10R
12 vegetarian items=12V
@
A)there are 7combination 3ways of selecting 3out of 7 poultry items
From the formula nCr=n!/(n-r)!r!
7C3=7!/(7-3)!3!=7!/4!×3!=35choices
b)total items available=7p+10R+12V(denotation explained above)=29items
Choosing 6items implies
29C6=29!/(29-6)!×6!
29!/23!×6!=475,020 ways
C)7C2+10C2+12C2
7!/5!2!+10!/8!2!+12!/10!2!
21+45+66=132 choices
D) probability (choosing 2items from each class)=
7C2+10C2+12C2/29C6
Where 29C6 represent total probable.
21+45+66/29!/23!6!
=132/475020=0.000278choices
E)for meats to be in the majority on a 6choices selection impliee that vegetarian items will be
0,1 or2i.e combination of vegetarian and meat will be(0,6)or(1,5)or(2,4) .
Prob(0veg)+prob(1veg item) or prob(2veg items)
12C0+12C1+12C2/29C6
=1+12+66/475,020
=0.000166
The volume of seeds in the package must be equal to the volume of the feeder in order to fill it completely. The volume of the conic feeder is given by:
V(f) = (πr²h)/3
And volume of the cylindrical package is given by:
V(p) = πr²h
Equating the two and substituting values:
(π x 3² x 24)/3 = π x 6² x h
h = 2 inches
Thirty-three percent of all students at a high school like beef stew. Put of three hundred students, forty are selected randomly and asked whether they liked beef stew. If liking beef stew is a success, the probability of a failure for this binomial experiment would be 0.67. The answer would be letter D.
Answer:
Can I see the sign?
Step-by-step explanation:
It wouldn't let me post, so I screenshotted:
