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Rudiy27
3 years ago
5

The price, P, of a certain stock is given by the formula P = -6t + 50 when t is the number of years since 2000. Find the price o

f the stock in the year 2000 and the year 2004
Mathematics
1 answer:
oksian1 [2.3K]3 years ago
3 0

Answer:

year 2000: P = 50

year 2004: P = 24

Step-by-step explanation:

t is the number of years since 2000, so for the year 2000, we have that t = 0.

Using this value in the equation, we find that:

P = -6 * 0 + 50 = 50

The price of the stock in year 2000 is 50.

For the year 2004, we have that t = 4, so using this value in the equation for P, we have:

P = -6 * 4 + 50 = -24 + 50 = 26

The price of the stock in year 2004 is 24.

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Transitive Property
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3 years ago
Pippi sold ten more cups of lemonade that cups of iced tea. She sold 120 cups in all. How many cups of lemonade did she sell?
Kamila [148]

Answer:

65  cups

Step-by-step explanation:

If she sold 10 more cups of lemonade than tea and sold 120 cups total.  I first would subtract 10 cups from 120 =110.  then I divide 110 /2 = 55 cups

The 55 cups makes it equal then I add the 10 cups back to the Lemonade to get 55+10 = 65

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7 0
3 years ago
How to do the problem
marta [7]
There are 153 people who each ate 1/4 pounds. Therefore, the amount of watermelon eaten is 153/4 pounds.
The amount of watermelon served is
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=  \frac{33}{4}  +  \frac{37}{4}  +  \frac{71}{8}  +  \frac{77}{8}  +  \frac{43}{4}  \\  =  \frac{33 \times 2}{4 \times 2}  +  \frac{37 \times 2}{4 \times 2}  +  \frac{71}{8}  \\  +  \frac{77}{8}  +  \frac{43 \times 2}{4 \times 2}
=  \frac{66 + 74 + 71 + 77 + 86}{8}
=  \frac{374}{8}  =  \frac{186}{4}
There is 186/4 total watermelon. Minus the 153/4 that was eaten,
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The leftover watermelon is 8 & 1/4 pounds.
6 0
3 years ago
3(x-4) + 2x - y2 for x = 5
Alborosie

Answer:

there is some of it sorry cant realy help

Step-by-step explanation:

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6 0
3 years ago
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Marrrta [24]

Answer:

A link for a calculator that I use for ratios

Step-by-step explanation:

https://www.calculatorsoup.com/calculators/math/ratios.php

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3 years ago
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