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serious [3.7K]
3 years ago
9

You are buying markers for the students in first grade. Each student will get 5 markers. There are 16 students in one class and

19 students in the other class. How many markers do you need to buy?
Mathematics
2 answers:
Masja [62]3 years ago
6 0
52 markers that you will need to buy.
SVEN [57.7K]3 years ago
6 0
You would need to buy 175 markers

5 markers (each student gets 5) times 16 (cause there's 16 students in class)=80 markers needed for the first class

5 markers (each student gets 5) times 19 (cause there's 19 students in the class)=95 markers needed for the second class
 
Add both together 80+95 and u get ur answer which is 175 markers 

Hope this helps! :)
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Each month, Anna pays $630 in rent. How much rent does she pay over the course of 18 months?
Ilia_Sergeevich [38]

Answer:

$11,340

Step-by-step explanation:

1 month: 630

18 months: 18×630=11,340

7 0
3 years ago
1. determine if the functions are inverse functions
kirill115 [55]

Answer:

<u>Question 1</u>

The function f(x) = x + 6 is one-to-one, so it does have an inverse.

The inverse of +6 is -6, so f^{-1}(x)=x-6

Therefore, g(x) is the inverse of f(x).

<u>Question 2</u>

The function f(x) = -3x -9 is one-to-one, so it does have an inverse.

To find the inverse, replace f(x) with y:

\implies y = -3x -9

Rearrange the equation to make x the subject:

\implies y+9= -3x

\implies x=-\dfrac13(y+9)

\implies x=-\dfrac13y-3

Replace x with f^{-1}(x) and y with x:

\implies f^{-1}(x)=-\dfrac13x-3

Therefore, g(x) is the inverse of f(x).

5 0
2 years ago
If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by y = 70t-16t^2.

To find : The average velocity for the time period beginning when t = 2 and lasting.  a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :    

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}

(\text{Average velocity})_{0.1\ s}=696\ ft/s

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}

(\text{Average velocity})_{0.01\ s}=7536\ ft/s

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}  

(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}

(\text{Average velocity})_{0.001\ s}=75936\ ft/s

5 0
3 years ago
Which expression is equivalent to (-1.3x-4.5) - (-2.1x+3.6)?
timurjin [86]

Equivalent expressions are expressions with the same value.

The equivalent expression of (-1.3x - 4.5)- (-2.1x + 3.6) is 0.8x -8.1

Given that:

(-1.3x - 4.5)- (-2.1x + 3.6)

Open brackets

(-1.3x - 4.5)- (-2.1x + 3.6) = -1.3x - 4.5+ 2.1x - 3.6

Collect like terms

(-1.3x - 4.5)- (-2.1x + 3.6) = -1.3x + 2.1x - 4.5 - 3.6

(-1.3x - 4.5)- (-2.1x + 3.6) = 0.8x -8.1

Hence, the equivalent of (-1.3x - 4.5)- (-2.1x + 3.6) is 0.8x -8.1

Read more about equivalent expressions at:

brainly.com/question/18257981

6 0
3 years ago
The half-life of cobalt-60 (used in
Likurg_2 [28]

Answer:

6.25 gm left

Step-by-step explanation:

Find the number of half lives in 26.3 years

   26.3 / 5.26 = 5 half lives

(1/2)  ^5   = 1/32 nd  of the original will be left

   1/32 * 200g = 6.25 gm left

5 0
2 years ago
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