Answer:
4/9
Step-by-step explanation:
Not sure if my picture answer make sense so, when you have a^2 and b^2 to find c^2 u add then and then square root it to get c. e.g 81^2 + 108^2 = 18225 then u square root it and get 135. when u are given the hypotenuse (which is always c^2) u take that away from the a^2/b^2 and square root. e.g 8^2-4^2 which is 48 which can’t be square rooted so just leave as root48
Answer:
1. Point C ( 0; 5 )
2. Point K ( 2; -3 )
3. Point N ( -6; -5 )
Look, here ( A; B ) A is located in x coordinate and B is located in y coordinate
Answer:
Four hundred and eighty nine thousand, five hundred and seventy
Answer:
a=k1![\sqrt[3]{B}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7BB%7D)
B=125
Step-by-step explanation:
Given :
a=3
B=64
According to question
a ∝ ![\sqrt[3]{B}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7BB%7D)
therefore
a=k1
........Eq(1)
K1=
......Eq(2)
Putting the value of a and B we get in Eq(2) we get

Putting the value of k1 in Eq(1)
.......................Eq(3)
putting the value of a=15/4 IN Eq(3) we get
![\frac{15}{4}\ =\frac{3}{4} \sqrt[3]{B} \\\\\sqrt[3]{B}\ =\ 5\\Cubing\ both\ side\ we\ get\\B=125](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B4%7D%5C%20%3D%5Cfrac%7B3%7D%7B4%7D%20%5Csqrt%5B3%5D%7BB%7D%20%20%5C%5C%5C%5C%5Csqrt%5B3%5D%7BB%7D%5C%20%3D%5C%205%5C%5CCubing%5C%20%20both%5C%20%20side%5C%20%20we%5C%20%20get%5C%5CB%3D125)