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matrenka [14]
3 years ago
13

You come across a box of perfume what should you do Amazon

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0
Take it back to the original owner
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2) Phillip has 8 red balls, 3 green balls, 6 yellow balls, 3 orange balls, 13 black balls
AVprozaik [17]
Mean 6.6
Median 6
Mode 3
Range 10

not positive on the 6.6 but the rest should be good
5 0
3 years ago
Please help thanks in advance
Over [174]
\frac{2(5)^2}{5} +5(100-15(5))\\\\  \frac{2*25}{5}+5(100-15(5))\\\\ \frac{50}{5}+5(100-15(5))\\\\ 10+5(100-15(5))\\\\ 10+5(100-75)\\\\ 10+5(25)\\\\ 10+125\\\\ 135\\\\ Final answer: 135\\
8 0
3 years ago
Please answer number 40 pls
kvasek [131]

Answer:

A is the answer

Step-by-step explanation:

m¹⁶/4n¹²

4 0
3 years ago
explain how you would find how many 1 1/2 cup servings there are in a pot that contains 22 1/2 cups of soup.
11Alexandr11 [23.1K]

Step-by-step explanation:

multiply the 1 1/2 by 2 to get 3.

find the closest number that is divisible by 3

3*7 is 21.

We now have to multiply 7 by 2 since we did that to our mixed number to get a whole number.

There is still a 1 1/2 left over. Simply add 1 to 14.

3 0
3 years ago
Read 2 more answers
I’m confused and don’t have an angle tool to even try to do the question
yanalaym [24]
<h3>Answer:   40</h3>

=================================================

Explanation:

JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.

See the diagram below.

The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)

We know that JN = 60

Let x = JQ and y = QN

The ratio of x to y is x/y and this is 2/1

x/y = 2/1

1*x = y*2

x = 2y

Now use the segment addition postulate

JQ + QN = JN

x + y = 60

2y + y = 60

3y = 60

y = 60/3

y = 20

QN = 20

JQ = 2*y = 2*QN = 2*20 = 40

--------------

We have

JQ = 40 and QN = 20

We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.

7 0
3 years ago
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