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andrezito [222]
3 years ago
11

HEALP!

Mathematics
2 answers:
Stels [109]3 years ago
8 0

Answer:

Step-by-step explanation:

Point A = (-2,1)

Point B = (5,3)

Point C = (-4,-5)

Point D = (0,-6)

Kipish [7]3 years ago
6 0

Answer:

A) (-2,1)

B) (5,3)

C) (-4,-5)

D) (0,-6)

You might be interested in
A factory ship the 100 boxes with 15 skateboards in each box and 10 boxes with 15 helmets in each box
netineya [11]

Answer:

150(10s + h)

Step-by-step explanation:

We need to write an expression for the total items they shipped.

Let each skateboard be s.

Let each helmets be h.

The factory ships 100 boxes with 15 skateboards in each box. That is:

100 * (15 * s) = 1500s

The factory ships 10 boxes with 15 helmets in each box. That is:

10 * (15 * h) = 150h

The total number of items shipped is therefore:

1500s + 150h = 150(10s + h)

This expression represents the total number of items shipped.

5 0
3 years ago
Complete the table to represent how much each individual monthly deposit of $50 will be worth at the end of 12 months.
densk [106]
Hold on let me go do my research I’ll brb .
3 0
3 years ago
Find all solutions of each equation on the interval 0 ≤ x < 2π.
Korvikt [17]

Answer:

x = 0 or x = \pi.

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}.

\displaystyle \sec{x} = \frac{1}{\cos{x}}.

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, \sin^{2}{x} = 1 - \cos^{2}{x}. Therefore, for the square of tangents,

\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}.

This equation will thus become:

\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2.

To simplify the calculations, replace all \cos^{2}{x} with another variable. For example, let u = \cos^{2}{x}. Keep in mind that 0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1.

\displaystyle \frac{1 - u}{u^{2}} + \frac{2}{u} - \frac{1 - u}{u} = 2.

\displaystyle \frac{(1 - u) + u - u \cdot (1- u)}{u^{2}} = 2.

Solve this equation for u:

\displaystyle \frac{u^{2} + 1}{u^{2}} = 2.

u^{2} + 1 = 2 u^{2}.

u^{2} = 1.

Given that 0 \le u \le 1, u = 1 is the only possible solution.

\cos^{2}{x} = 1,

x = k \pi, where k\in \mathbb{Z} (i.e., k is an integer.)

Given that 0 \le x < 2\pi,

0 \le k.

k = 0 or k = 1. Accordingly,

x = 0 or x = \pi.

8 0
3 years ago
Read 2 more answers
M=p/n+4 make n the subject​
Kipish [7]

Answer:

n = \frac {p - 4m}{m}

Step-by-step explanation:

Given the algebraic expression;

m = \frac {p}{n + 4}

To make n the subject of formula.

Cross-multiplying, we have;

m*(n+4) = p

mn + 4m = p

Rearranging the equation, we have;

mn = p - 4m

n = \frac {p - 4m}{m}

6 0
3 years ago
Read 2 more answers
If ps=36,pq=3x+5, qr=6x-10,rs=36, then pr=
finlep [7]

Answer:

5444545645645

Step-by-step explanation:

567456454351

7 0
3 years ago
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