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enyata [817]
4 years ago
7

How many ft2 are in a rectangle 12.6 yd long and 8.6 yd wide? (A = lw)​

Mathematics
1 answer:
Usimov [2.4K]4 years ago
3 0

Answer:

108.36 ft2

Step-by-step explanation:

Use the facts we already know and plug them into the equation.

a=12.6(8.6)

If we multiply both factors, we get 108.36.

So, the rectangle is 108.36 ft2

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About 39,402.

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All numbers that are between 20 and 40 that are divisible by 4
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24, 28, 32, 36.

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Multiply (4a-2)(a+7)
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3 years ago
Expand and combine like terms (3z^5 +7z^2)^2
AVprozaik [17]

Answer:

\displaystyle{(3z^5+7z^2)^2 = 9z^{10}+42z^7 + 49z^4 }

Step-by-step explanation:

Since it's a perfect square, we can simply use the formula:

\displaystyle{(ax+by)^2 = a^2x^2+2abxy+b^2y^2}

Given the perfect square expression \displaystyle{(3z^5+7z^2)^2}. Apply perfect square formula:

\displaystyle{(3z^5+7z^2)^2 = 3^2(z^5)^2+2(3)(7)(z^5)(z^2) + 7^2(z^2)^2 }

Knowing laws of exponent is mandatory when it comes to algebra. Recall that:

\displaystyle{(a^m)^n = a^{mn}}\\\\\displaystyle{a^m \cdot a^n = a^{m+n}}

Apply laws of exponent to simplify the terms or expression:

\displaystyle{(3z^5+7z^2)^2 = 9z^{10}+42z^7 + 49z^4 }

Since there are no like-terms to do operation with (these terms have different degrees so they are not considered to be like-terms.) Therefore, the final answer is:

\displaystyle{(3z^5+7z^2)^2 = 9z^{10}+42z^7 + 49z^4 }

8 0
1 year ago
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