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liberstina [14]
3 years ago
5

Sixty percent of students in Mariana's class has a pet. If 12 students have pets, how many students are in the class

Mathematics
1 answer:
Likurg_2 [28]3 years ago
6 0
20 students, because 12 is 60% of 20.
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Add (1.3t3 + 0.4t2 – 24t) + (8 – 18t + 0.6t2) For each term in the second polynomial, enter the letter showing where that term s
nignag [31]

Answer:

(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2) = 1.3t^3 + t^2 -42t  + 8

Step-by-step explanation:

Given

(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2)

Required

Solve

We have:

(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2)

Collect like terms

1.3t^3 + 0.6t^2 + 0.4t^2 - 24t- 18t  + 8

1.3t^3 + t^2 -42t  + 8

So:

(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2) = 1.3t^3 + t^2 -42t  + 8

8 0
2 years ago
1/2(2+a)=3a+4/3 solve it
Mumz [18]
1/2(2+a)=3a+4/3

first, you use the distributive property<span>

</span>then your problem changes to...

1 + 1/2a = 3a + 4/3

then you subtract 1/2a with 3a

1  = 2 1/2a +4/3
<span>
now you subtract 1 with 4/3
</span>
-1/3 = 2 1/2a

now you divide -1/3 with 2 1/2a 

-2/15 = a

A = -2/15 is your answer. Hope this helps :)


4 0
3 years ago
Which digit has the greatest value in the number 1,567
Nookie1986 [14]
Seven has the greatest value as a digit, but 1, 000 has the greatest standard form value.
7 0
3 years ago
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;l
sergiy2304 [10]

Answer:

0ppppppppppppppppppppppppppp

7 0
3 years ago
Please help!! thank you.
Zina [86]

(A) Product of -2x^{3}+x-5 and x^{3}-3x-4 is:

(-2x^{3}+x-5)(x^{3}-3x-4)

=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)

=(-2x^{3})(x^{3})+(-2x^{3})(-3x)+(-2x^{3})(-4)+x(x^{3})+(x)(-3x)+(x)(-4)+(-5)(x^{3})+(-5)(-3x)+(-5)(-4)

=-2x^{6}+6x^{4}+8x^{3}+x^{4}-3x^{2}-4x-5x^{3}+15x+20

=-2x^{6}+6x^{4}+x^{4}+ 8x^{3}-5x^{3}-3x^{2}-4x+15x+20

=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20

(B) Yes.

Product of -2x^{3}+x-5 and x^{3}-3x-4 = Product of x^{3}-3x-4 and -2x^{3}+x-5 because multiplication is commutative.

Commutative Property of multiplication says that a.b = b.a.

Thus, multiplication is same irrespective of the order of two numbers.



5 0
3 years ago
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