Answer:
no solution, 1/3x - 2 ≠ 1/3x + 3
where is the 'y'?
Step-by-step explanation:
Simplifying
x + 0.7 = 1 + -0.2x
Reorder the terms:
0.7 + x = 1 + -0.2x
Solving
0.7 + x = 1 + -0.2x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '0.2x' to each side of the equation.
0.7 + x + 0.2x = 1 + -0.2x + 0.2x
Combine like terms: x + 0.2x = 1.2x
0.7 + 1.2x = 1 + -0.2x + 0.2x
Combine like terms: -0.2x + 0.2x = 0.0
0.7 + 1.2x = 1 + 0.0
0.7 + 1.2x = 1
Add '-0.7' to each side of the equation.
0.7 + -0.7 + 1.2x = 1 + -0.7
Combine like terms: 0.7 + -0.7 = 0.0
0.0 + 1.2x = 1 + -0.7
1.2x = 1 + -0.7
Combine like terms: 1 + -0.7 = 0.3
1.2x = 0.3
Divide each side by '1.2'.
x = 0.25
Simplifying
x = 0.25
I only know 1 way.
Answer:

Step-by-step explanation:
Given
--- selected customers
--- those that are expected to use the restroom
--- proportion that uses the restroom
Required

The question illustrates binomial probability and the formula is:

So, we have:




Answer:
-2
Step-by-step explanation:
I actually just did functions in math at the end of last semester I offer you my condolences dude
Problem 2
Part (a)
The 3D shape formed when rotating around the y axis forms a pencil tip
The shape formed when rotating around the x axis is a truncated cone turned on its side.
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Part (b)
Check out the two diagrams below.
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Problem 3
Answer: Choice A and Choice C
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Explanation:
Think of stacks of coins. Let's say we had 2 stacks of 10 quarters each. The quarters are identical, so they must produce identical volumes. Those sub-volumes then add up to the same volume for each stack. Now imagine one stack is perfectly aligned and the other stack is a bit crooked. Has the volume changed for the crooked stack? No, it hasn't. We're still dealing with the same amount of coins and they yield the same volume.
For more information, check out Cavalieri's Principle.
With all that in mind, this leads us to choice C. If the bases are the same, and so are the heights, then we must be dealing with the same volumes.
On the other hand, if one base is wider (while the heights are still equal) then the wider based block is going to have more volume. This leads us to choice A.