7,500 x 2 = 15,000
you know you can just use a calculator...
Answer:
a. dy/dx = -2/3
b. dy/dx = -28
Step-by-step explanation:
One way to do this is to assume that x and y are functions of something else, say "t", then differentiate with respect to that. If we write dx/dt = x' and dy/dt = y', then the required derivative is y'/x' = dy/dx.
a. x'·y^3 +x·(3y^2·y') = 0
y'/x' = -y^3/(3xy^2) = -y/(3x)
For the given point, this is ...
dy/dx = -2/3
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b. 2x·x' +x^2·y' -2x'·y^3 -2x·(3y^2·y') + 0 = 2x' + 2y'
y'(x^2 -6xy^2 -2) = x'(2 -2x +2y^3)
y'/x' = 2(1 -x +y^3)/(x^2 +6xy^2 -2)
For the given point, this is ...
dy/dx = 2(1 -0 +27)/(0 +0 -2)
dy/dx = -28
_____
The attached graphs show these to be plausible values for the derivatives at the given points.
That depends. What are you trying to find? The formula for the perimeter? The formula for the area?
D................................l
Answer:
(x - 5)^2 + y^2 = 225/4,
or you could write it as (x - 5)^2 + y^2 = 56.25.
Step-by-step explanation:
The factor form is
(x - h)^2 + (y - k)^2 = r^2 where the center is (h, k) and r = the radius.
So we have:
(x - 5)^2 + (y - 0)^2 = r^2
As the point (-1, 9/2) is on the line:
(-1 - 5)^2 + (9/2)^2 = r^2
r^2 = 36 + 81/4
r^2 = 225/4.
So substituting for r^2:
(x - 5)^2 + (y - 0)^2 = 225/4
(x - 5)^2 + y^2 = 225/4 is the standard form.