Answer:
What is P(A), the probability that the first student is a girl? (3/4)
What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)
What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)What is P(A and B), the probability that the first student is a girl and the second student is a girl? (1/2)
The probability that the first student is a girl is (3/4), likewise for the 2nd 3rd and 4th it's still (3/4). The order you pick them doesn't matter.
However, once you're looking at P(A and B) then you're fixing the first position and saying if the first student is a girl what's the probability of the second student being a girl.
Answer:
first one: a,d,e
second one: d
Step-by-step explanation:
pemdas
Using proportions, it is found that 1685% of an hour passes between 11:24 am and 415 am.
<h3>What is a proportion?</h3>
A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.
One hour is composed by 60 minutes. Between 11:24 am and 4:15 am, there are 16 hours and 51 minutes, hence the number of minutes is given by:
M = 16 x 60 + 51 = 1011 minutes.
As a percentage of one hour = 60 minutes, we have that this measure is:
1011/60 x 100% = 1685%.
Hence 1685% of an hour passes between 11:24 am and 415 am.
More can be learned about proportions at brainly.com/question/24372153
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