Answer:
D. The system is in echelon form.
Step-by-step explanation:
Check attachment
Answer:
The integers are 4 and 7 or -2 and 1.
Step-by-step explanation:
You can make a system of equations with the description of the two integers.
1. x = y + 3
2. 2x + 2 = y^2
The simplest and the fastest way to solve this system in this case is substitution. You can substitute x for y + 3 in the second equation.
1. x = y + 3
2. 2(y + 3) + 2 = y^2
Now simplify and solve the second one. For convenience, I will just disregard the first equation for now.
2y + 6 + 2 = y^2
y^2 - 2y - 8 = 0
You can factor this equation to solve for y.
(y - 4) (y + 2) = 0
y = 4, y = -2
Now we can substitute the value of y for x in the first equation.
x = 7, x = 1
^ means to the power of or exponent
logb(x) = y is b^y = x
<span>Simplifying
-15x2 + -2x + 8 = 0
Reorder the terms:
8 + -2x + -15x2 = 0
Solving
8 + -2x + -15x2 = 0
Solving for variable 'x'.
Factor a trinomial.
(2 + -3x)(4 + 5x) = 0
Subproblem 1Set the factor '(2 + -3x)' equal to zero and attempt to solve:
Simplifying
2 + -3x = 0
Solving
2 + -3x = 0
Move all terms containing x to the left, all other terms to the right.
Add '-2' to each side of the equation.
2 + -2 + -3x = 0 + -2
Combine like terms: 2 + -2 = 0
0 + -3x = 0 + -2
-3x = 0 + -2
Combine like terms: 0 + -2 = -2
-3x = -2
Divide each side by '-3'.
x = 0.6666666667
Simplifying
x = 0.6666666667
Subproblem 2
Set the factor '(4 + 5x)' equal to zero and attempt to solve:
Simplifying
4 + 5x = 0
Solving
4 + 5x = 0
Move all terms containing x to the left, all other terms to the right.
Add '-4' to each side of the equation.
4 + -4 + 5x = 0 + -4
Combine like terms: 4 + -4 = 0
0 + 5x = 0 + -4
5x = 0 + -4
Combine like terms: 0 + -4 = -4
5x = -4
Divide each side by '5'.
x = -0.8
Simplifying
x = -0.8
Solutionx = {0.6666666667, -0.8}</span>
5/13t= -9
Then t =( -9*13) / 5
T=-23.4
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